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AQA A2 Mathematics MPC4 Core 4 - 9th June 2015 [Discussion & unofficial markscheme] Watch

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    (Original post by Jimmy20002012)
    Struggling with part cii, I have found vector BP, and used distance formula, and on gained a quadratic in mu, and found mu to 5/3 and 1/3 but not sure why you have to do vector of PB to get correct answer I though it did not matter which way round it was. ???

    Attachment 399599


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    It doesn't matter whether you've found \vec{BP} or \vec{PB} because |\vec{BP}|=|\vec{PB}|.

    The mark scheme says that:

    \mu=\dfrac{-1}{3}

    or

    \mu=\dfrac{-5}{3}

    Is this what you've got? Or did you end up with

    \mu=\dfrac{1}{3}

    And

    \mu=\dfrac{5}{3}
    ?


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    God Please help me in this exam 🙏🏻


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    (Original post by Ruxy)
    God Please help me in this exam 🙏🏻


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    Haha! How are you finding Maths revision?


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    (Original post by CD223)
    It doesn't matter whether you've found \vec{BP} or \vec{PB} because |\vec{BP}|=|\vec{PB}|.

    The mark scheme says that:

    \mu=\dfrac{-1}{3}

    or

    \mu=\dfrac{-5}{3}

    Is this what you've got? Or did you end up with

    \mu=\dfrac{1}{3}

    And

    \mu=\dfrac{5}{3}
    ?


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    Yes I had the positive answers? Here's my solution
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    (Original post by Jimmy20002012)
    Yes I had the positive answers? Here's my solution
    Name:  ImageUploadedByStudent Room1431785261.314850.jpg
Views: 124
Size:  161.0 KB


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    The vector \vec{BP} should read;

    \begin{bmatrix} -2 - 2\mu \\ -5 - 5\mu \\ -4 - 4\mu \end{bmatrix}


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    (Original post by CD223)
    The vector \vec{BP} should read;

    \begin{bmatrix} -2 - 2\mu \\ -5 - 5\mu \\ -4 - 4\mu \end{bmatrix}


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    Hahahaha now I look like an idiot.


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    (Original post by Jimmy20002012)
    Hahahaha now I look like an idiot.


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    Not at all! Easy mistake to make!


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    Can somebody help me on 8c & d. I have +15 where the book says +20 in 8c and in 8d I'm stuck.

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    (Original post by the_googly)
    Can somebody help me on 8c & d. I have +15 where the book says +20 in 8c and in 8d I'm stuck.

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    Is this correct?
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    (Original post by CD223)
    Is this correct?
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    part d is incorrect
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    (Original post by the_googly)
    part d is incorrect
    Ah sorry of course yes.

    The tangent at B is meant to read:

    

3y - 4x + 12 = 0

    This gives:

    

P = \left(-1, -\dfrac{16}{3}\right)

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    (Original post by jjsnyder)
    Can you tell me what your teacher says when you ask him?
    He says the factor formulae are required for other boards but not AQA.


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    (Original post by CD223)
    He says the factor formulae are required for other boards but not AQA.


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    Lol! Why's it in the CGP book then?
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    (Original post by lionelmessi19)
    Lol! Why's it in the CGP book then?
    In all honesty I'm not sure. If it's not in the specification it's not required.


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    (Original post by CD223)
    In all honesty I'm not sure. If it's not in the specification it's not required.


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    Yeah, you're right! I had a look and its not in there.. Not quite sure why cgp have put it in the revision guide! I haven't seen it in class either
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    (Original post by lionelmessi19)
    Yeah, you're right! I had a look and its not in there.. Not quite sure why cgp have put it in the revision guide! I haven't seen it in class either
    The specification seems to have every possible sub topic within a chapter


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    (Original post by CD223)
    The specification seems to have every possible sub topic within a chapter


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    Yeah, apart from that weird trig one. Would be so peak if that came up!
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    (Original post by lionelmessi19)
    Yeah, apart from that weird trig one. Would be so peak if that came up!
    If it came up they'd have to guide us through it. Plus there'd be 1000s of complaints to the board haha.


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    (Original post by CD223)
    If it came up they'd have to guide us through it. Plus there'd be 1000s of complaints to the board haha.


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    Well the guidance better be good then! Could cost my grade lol!!
    But there will still be people like you who will get it right! I know hahaha
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    (Original post by lionelmessi19)
    Well the guidance better be good then! Could cost my grade lol!!
    But there will still be people like you who will get it right! I know hahaha
    It's nice you have so much faith in me - but I won't get it right

    Ordered a graphical calculator today just in case lol.


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