AS Chemistry- helping each other out!
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Original post by Dinaa
Bunking school again 
:spank:
do you get study leave?
Original post by James A
do you get study leave?
do you get study leave?
Nope
Original post by EXAMSEXAMSEXAMS
lol
Lol your name bro
Exam sex? Wtf
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Original post by Dinaa
Nope
Wow that is pretty stupid
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Original post by samb1234
Hah what me bunking or not having study leave?
Original post by Dinaa
Hah what me bunking or not having study leave?
Not having study leave. Why don't they want you to have study leave?
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Original post by samb1234
No idea
Original post by Dinaa
No idea
If i was you i would bunk and study at home
College at this time of year is largely useless
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Original post by life's a pain
If i was you i would bunk and study at home
College at this time of year is largely useless
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College at this time of year is largely useless
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That is what I have been doing, problem is I procrastinate badly when I stay at home.
So I bunk and hit the library
Original post by life's a pain
If i was you i would bunk and study at home
College at this time of year is largely useless
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College at this time of year is largely useless
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Yeah I've been forced to stay here until 2pm even though I only had 1 lesson which was first period
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Original post by James A
do you get study leave?
do you get study leave?
I don't either :/
meh i just revise the whole day at college or go library
Original post by ThatGuyRik
I don't either :/
meh i just revise the whole day at college or go library
meh i just revise the whole day at college or go library
I didn't get study leave either back in the days
We were allowed to go to the school library though
Guys/girls, this question has been bothering me for a while now, would really like some help, would be much appreciated.
0.85g of an indigestion tablet containing calcium hydroxide was was reacted with 50cm3 of 1.00M hydrochloric acid. the resulting solution was made up to 250m3 in a volumetric flask. 25cm3 of this solution required 30.80cm3 of 0.100M sodium hydroxide for neutralisation. calculate the per cent purity, by mass of the calcium hydroxide.
So I calculated the moles of sodium Hydroxide, by using n= cv, so n = (0.100 x 30.80/1000) =0.00308 Moles
NaOH + HCL -> Nacl + H20, so they react 1:1, the moles of HCl must also equal 0.00308 moles.
but now what do I do?
0.85g of an indigestion tablet containing calcium hydroxide was was reacted with 50cm3 of 1.00M hydrochloric acid. the resulting solution was made up to 250m3 in a volumetric flask. 25cm3 of this solution required 30.80cm3 of 0.100M sodium hydroxide for neutralisation. calculate the per cent purity, by mass of the calcium hydroxide.
So I calculated the moles of sodium Hydroxide, by using n= cv, so n = (0.100 x 30.80/1000) =0.00308 Moles
NaOH + HCL -> Nacl + H20, so they react 1:1, the moles of HCl must also equal 0.00308 moles.
but now what do I do?
Original post by alanahart
Nope, the double bond of the alkene breaks allowing the carbon to form bonds with the hydrogen and bromine during the reaction. This now means it is an alkane (the diagram underneath).
Thanks for replying.
No I understand but it says the method for the reaction is to bubble hydrogen halides (gases @ rt) into liquid alkANE, but if this happened no reaction would occur. The hydrogen halide gas should be bubbled into a liquid alkENE....right?
Original post by Cherry82
How do you mean? Like do two full past papers in those two weeks? Then use the other papers to revise?
I agree, the book takes ages. And I'm still in the first unit. I wonder if I am even going to finish this all.
I agree, the book takes ages. And I'm still in the first unit. I wonder if I am even going to finish this all.
Yeah that's what I meant, wow that's behind but its possible, you'll just need to put in a lot of work! You'll be fine
Original post by Frosty_A
Guys/girls, this question has been bothering me for a while now, would really like some help, would be much appreciated.
0.85g of an indigestion tablet containing calcium hydroxide was was reacted with 50cm3 of 1.00M hydrochloric acid. the resulting solution was made up to 250m3 in a volumetric flask. 25cm3 of this solution required 30.80cm3 of 0.100M sodium hydroxide for neutralisation. calculate the per cent purity, by mass of the calcium hydroxide.
So I calculated the moles of sodium Hydroxide, by using n= cv, so n = (0.100 x 30.80/1000) =0.00308 Moles
NaOH + HCL -> Nacl + H20, so they react 1:1, the moles of HCl must also equal 0.00308 moles.
but now what do I do?
0.85g of an indigestion tablet containing calcium hydroxide was was reacted with 50cm3 of 1.00M hydrochloric acid. the resulting solution was made up to 250m3 in a volumetric flask. 25cm3 of this solution required 30.80cm3 of 0.100M sodium hydroxide for neutralisation. calculate the per cent purity, by mass of the calcium hydroxide.
So I calculated the moles of sodium Hydroxide, by using n= cv, so n = (0.100 x 30.80/1000) =0.00308 Moles
NaOH + HCL -> Nacl + H20, so they react 1:1, the moles of HCl must also equal 0.00308 moles.
but now what do I do?
where is this question from?
because you sure it's 0.85 not 8.5
(edited 8 years ago)
Original post by k.wills
ive done bio epma anyone wanna swap for chem
Look at the first page of this thread. First post. Read.
Original post by frozo123
where is this question from?
because you sure it's 0.85 not 8.5
because you sure it's 0.85 not 8.5
Yep, I'm sure.
hey everyone, can someone please help me with this?
when do you comment about electrons filling orbitals and when electrons fill subshells?
i don't quite know when to use with term :/
when do you comment about electrons filling orbitals and when electrons fill subshells?
i don't quite know when to use with term :/
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