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    The Avogadro constant is 6.0 x 1023 mol–1.
    The number of atoms in1 mol of dinitrogen tetroxide, N2O4, is
    A 3.6 × 1024
    B 1.8 × 1024
    C 6.0 × 1023
    D 1.0 × 1023
    Spoiler:
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    I got A, but the answer is D? help please!
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    (Original post by alevels2k15)
    The Avogadro constant is 6.0 x 1023 mol–1.
    The number of atoms in1 mol of dinitrogen tetroxide, N2O4, is
    A 3.6 × 1024
    B 1.8 × 1024
    C 6.0 × 1023
    D 1.0 × 1023
    Spoiler:
    Show
    I got A, but the answer is D? help please!
    How did you get you answer, this has stumped me! Wonderful feeling since there are only a few hours to go until the exam!
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    (Original post by alevels2k15)
    The Avogadro constant is 6.0 x 1023 mol–1.
    The number of atoms in1 mol of dinitrogen tetroxide, N2O4, is
    A 3.6 × 1024
    B 1.8 × 1024
    C 6.0 × 1023
    D 1.0 × 1023
    Spoiler:
    Show
    I got A, but the answer is D? help please!

    (Original post by TheonlyMrsHolmes)
    How did you get you answer, this has stumped me! Wonderful feeling since there are only a few hours to go until the exam!

    Yes, there are 6.0 × 10^23 particles in any 1 mole. In this case the particles are molecules of N2O4, but the question didn't ask for the number of molecules of N2O4. It wants to know the number of atoms. In each molecule of N2O4 there are two atoms of N and four atoms of O, for a total of six atoms per molecule, so: (1 mol N2O4) x (6.0 × 10^23 molecules/mol) x (6 atoms/molecule) = 3.6 x 10^24 atoms total.
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    how do you find the maximum volume of a gas???
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    (Original post by alevels2k15)
    The Avogadro constant is 6.0 x 1023 mol–1.
    The number of atoms in1 mol of dinitrogen tetroxide, N2O4, is
    A 3.6 × 1024
    B 1.8 × 1024
    C 6.0 × 1023
    D 1.0 × 1023
    Spoiler:
    Show
    I got A, but the answer is D? help please!
    Are you sure it's not A? Cus I've also got A.. 6 atoms and cos it's 1 mol, the avogadro constant should stay the same, so  6 \times 6.0 \times 10 ^2^3
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    In the mark scheme, why is there 2 different ways of calculating percentage error? eg. if it's \pm 0.5 u'll have to multiple by  2 I guess? then divide by 100
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    (Original post by FluffyCherry)
    In the mark scheme, why is there 2 different ways of calculating percentage error? eg. if it's \pm 0.5 u'll have to multiple by  2 I guess? then divide by 100
    hi the question is wrong it june 2013 question 7 edexcel paper
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    (Original post by FluffyCherry)
    Are you sure it's not A? Cus I've also got A.. 6 atoms and cos it's 1 mol, the avogadro constant should stay the same, so  6 \times 6.0 \times 10 ^2^3
    yes it is A
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    (Original post by FluffyCherry)
    In the mark scheme, why is there 2 different ways of calculating percentage error? eg. if it's \pm 0.5 u'll have to multiple by  2 I guess? then divide by 100
    can tell me the question because I always get those question wrong
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    (Original post by Shadowfire123)
    can tell me the question because I always get those question wrong
    It's in the edexcel MAY 2013 paper, question 21 (c)
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    When 0.1 mol of atoms of an element reacts with chlorine,?there is an increase in mass of 7.1 g. please explain the element could be: carbon sodium magnesium aluminium
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    (Original post by FluffyCherry)
    It's in the edexcel MAY 2013 paper, question 21 (c)
    how would you work it out
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    (Original post by FluffyCherry)
    When 0.1 mol of atoms of an element reacts with chlorine,?there is an increase in mass of 7.1 g. please explain the element could be: carbon sodium magnesium aluminium

    you do 7.1 over 35.5 which gives you 0.2 mol this mean that its 1 -2 ratio between the element and chlorine now find which one it is
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    so this mean ITS magnesium is the answer C
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    (Original post by Shadowfire123)
    you do 7.1 over 35.5 which gives you 0.2 mol this mean that its 1 -2 ratio between the element and chlorine now find which one it is
    Spoiler:
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    so this mean ITS magnesium is the answer C

    Hey could you explain to me cis trana isomerism. idk how to look at it. The bottom and top or the left hand side to right hand side
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    .Name:  1432272059844-530285316.jpg
Views: 210
Size:  503.3 KB

    I said bring the tube lower and have the tube go directly into the tube.. idk and another point?
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    (Original post by Shadowfire123)
    how would you work it out
    0.5 x 2 x 100.

    you times 100 because in the question it says plus or minus 0.5.
    Then divide by 11, cus of the temperature rise, which is also mentioned in the question.
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    (Original post by Dinaa)
    .Name:  1432272059844-530285316.jpg
Views: 210
Size:  503.3 KB

    I said bring the tube lower and have the tube go directly into the tube.. idk and another point?
    Do u have the markscheme?
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    Could anyone list the calculations for unit 1 (edexcel)
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    (Original post by Dinaa)
    Hey could you explain to me cis trana isomerism. idk how to look at it. The bottom and top or the left hand side to right hand side
    cis is like scissors they are together on one side
    and trans is when they are different side
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    (Original post by FluffyCherry)
    0.5 x 2 x 100.

    you times 100 because in the question it says plus or minus 0.5.
    Then divide by 11, cus of the temperature rise, which is also mentioned in the question.
    why did you multiply it by 2
 
 
 
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