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    (Original post by jshep000)
    I'm afraid if you can't get/understand that then my friend....
    Fokin l0l
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    What possible uses could they ask about?
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    Remember, if it asks about atom economy and it is to do with an alkene reaction. It is 100% because it is an addition reaction and only forms one product!
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    Your notes are SAH cute.

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    (Original post by Anon_98)
    Your notes are SAH cute.

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    Made them at the start of the year so they are kinda basic
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    I need to get ready :erm:
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    (Original post by Dinaa)
    Made them at the start of the year so they are kinda basic
    Ah being modest huh.

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    (Original post by Dinaa)
    I need to get ready :erm:
    WELlllllL.. GET READY THEN.

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    (Original post by Shadowfire123)
    Yes, there are 6.0 × 10^23 particles in any 1 mole. In this case the particles are molecules of N2O4, but the question didn't ask for the number of molecules of N2O4. It wants to know the number of atoms. In each molecule of N2O4 there are two atoms of N and four atoms of O, for a total of six atoms per molecule, so: (1 mol N2O4) x (6.0 × 10^23 molecules/mol) x (6 atoms/molecule) = 3.6 x 10^24 atoms total.
    (Original post by TheonlyMrsHolmes)
    How did you get you answer, this has stumped me! Wonderful feeling since there are only a few hours to go until the exam!
    (Original post by FluffyCherry)
    Are you sure it's not A? Cus I've also got A.. 6 atoms and cos it's 1 mol, the avogadro constant should stay the same, so  6 \times 6.0 \times 10 ^2^3
    Apologies! Turns out i was looking at the incorrect Mark scheme!

    Made me feel really dumb lol
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    (Original post by Shadowfire123)
    make it simpler to understand
    what the hell, do you need him to draw it with crayons
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    (Original post by alevels2k15)
    Apologies! Turns out i was looking at the incorrect Mark scheme!

    Made me feel really dumb lol
    though so haha
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    (Original post by alevels2k15)
    Apologies! Turns out i was looking at the incorrect Mark scheme!

    Made me feel really dumb lol
    Thankgod because I lost all hope in myself since I couldn't do a simple avogardo question
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    How would you explain why the major product is made in electrophilic addition of hbr


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    If anyone here is doing OCR, can you help me out with question 4 c ii.
    Why do we need to divide the amount in moles by two?
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    (Original post by Supermanxxxxxx)
    How would you explain why the major product is made in electrophilic addition of hbr


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    It is made as major product because the carbocation is more stable because it has more different groups on it.
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    (Original post by Dinaa)
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    B?
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    (Original post by Dinaa)
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    Definetly c
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    (Original post by jshep000)
    B?
    (Original post by Mr.bob)
    Definetly c
    Oh god i thought B too..
 
 
 
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