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    (Original post by Super199)
    Question 1 was : "What change of functional group occurs during the oxidation"
    Also can you explain 3?
    Yeah, I mean which oxidation?

    3) when you oxidise an alcohol you get an aldehyde or ketone.

    However aldehyde can also be oxidised again to form a carboxylic acid by the same reagent so if you don't remove your product then this reaction will also occur.
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    (Original post by Random1357)
    Yeah, I mean which oxidation?

    3) when you oxidise an alcohol you get an aldehyde or ketone.

    However aldehyde can also be oxidised again to form a carboxylic acid by the same reagent so if you don't remove your product then this reaction will also occur.
    Partial oxidation
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    (Original post by Super199)
    Partial oxidation
    Of a primary alcohol?

    Alcohol -> aldehyde
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    jesus christ unit 2 chemistry is impossible for me, we've been taught it so terribly and i have the mock tomorrow, i know nothing

    in the unit 1 mock i got a C, 4 marks off a B, all i want at this point would be a C for both exams because I don't see myself getting above a B in chemistry because of this unit 2
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    (Original post by AyshaU)
    Thanks for the advice as in the January mocks I also got a u and some topics I completely understand whilst some of my knowledge is a bit shaky. Can I just ask what exam board did you do
    I do AQA, if you do the same as me please feel free to ask me anything.

    Don't worry about your U grade. When I did the CHEM2 MOCK in April (not March sorry) there were only topics that I understood completely like Maxwell-Boltzmann and Equilibria but the rest of the content was just mumbo jumbo. It'll take time and practise to get the grade you want, you'll be fine mate
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    Can someone give me the answer and working to this Q? its weird...


    Calculate the mass of 3-methylbutan-2-ol used by the student.

    3-methylbutan-2-ol + [O] = 3-methylbutan-2-one + H2O

    the 3-methylbutan-2-one weighed 2.15g

    The yield was 62.5%


    i will literally give you a rep eevery day forever if you give me a good answer <3
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    (Original post by Georgiam247)
    Can someone give me the answer and working to this Q? its weird...


    Calculate the mass of 3-methylbutan-2-ol used by the student.

    3-methylbutan-2-ol + [O] = 3-methylbutan-2-one + H2O

    the 3-methylbutan-2-one weighed 2.15g

    The yield was 62.5%


    i will literally give you a rep eevery day forever if you give me a good answer <3
    Convert your mass to moles.

    Divide by 0.63 yield

    Note Stoich is 1:1

    Multiply by Mr to give mass.
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    (Original post by Georgiam247)
    Can someone give me the answer and working to this Q? its weird...


    Calculate the mass of 3-methylbutan-2-ol used by the student.

    3-methylbutan-2-ol + [O] = 3-methylbutan-2-one + H2O

    the 3-methylbutan-2-one weighed 2.15g

    The yield was 62.5%


    i will literally give you a rep eevery day forever if you give me a good answer <3
    So Percentage yield= actual yield/ theoretical yield x100
    so 62.5/100= actual yield/ theoretical yield
    so theoretical yield= actual yield/ 0.625
    " " " = 2.15/ 0.625
    = 3.44g
    Number of moles= mass/mr
    Number of moles of 3-methylbutan-2-one= 3.44/ 86
    Number of moles= 0.0400 (3sf)
    1:1 mole ratio
    mass of 3methylbutan-2-ol= mr x number of moles
    " " " = 88 x 0.0400
    = 3.52g (3sf)
    ( I think )
    A2 student atm who got an A at AS
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    (Original post by frozo123)
    So Percentage yield= actual yield/ theoretical yield x100
    so 62.5/100= actual yield/ theoretical yield
    so theoretical yield= actual yield/ 0.625
    " " " = 2.15/ 0.625
    = 3.44g
    Number of moles= mass/mr
    Number of moles of 3-methylbutan-2-one= 3.44/ 86
    Number of moles= 0.0400 (3sf)
    1:1 mole ratio
    mass of 3methylbutan-2-ol= mr x number of moles
    " " " = 88 x 0.0400
    = 3.52g (3sf)
    ( I think )
    A2 student atm who got an A at AS


    Yesssssss that was my answer thank you so much
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    (Original post by Georgiam247)
    Yesssssss that was my answer thank you so much
    any other questions? want to use this thread for my revision haha
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    (Original post by frozo123)
    any other questions? want to use this thread for my revision haha

    Yeah that's a good idea but not right now, I am mentally exhausted after a practical exam in chemistry today! Maybe next week lol :P
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    (Original post by Georgiam247)
    Yeah that's a good idea but not right now, I am mentally exhausted after a practical exam in chemistry today! Maybe next week lol :P
    good luck for the results
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    (Original post by frozo123)
    good luck for the results
    Thank you!! Well done on getting an A at AS, I may need you again!
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    (Original post by Georgiam247)
    Thank you!! Well done on getting an A at AS, I may need you again!
    what exam board are you on?
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    (Original post by frozo123)
    what exam board are you on?
    OCR
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    (Original post by Georgiam247)
    OCR
    oh ok


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    (Original post by Georgiam247)
    OCR
    A or B? (Basically Salters or the other one)

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    (Original post by panda14)
    A or B? (Basically Salters or the other one)

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    what's the hype about salters?


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    (Original post by thatgr)
    jesus christ unit 2 chemistry is impossible for me, we've been taught it so terribly and i have the mock tomorrow, i know nothing

    in the unit 1 mock i got a C, 4 marks off a B, all i want at this point would be a C for both exams because I don't see myself getting above a B in chemistry because of this unit 2
    Just look through your textbook and make some notes! It's up to your what you get, i had a crap teacher and still got an A. Had to work my arse off but i got it
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    Anyone care to help me with a question.

    Use the data from the table above to calculate a value for the enthalpy of formation of ammonia?

    Why is it sum of bonds broken - sum of bonds made and not sum of products - sum of reactants?
 
 
 
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