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    (Original post by Kadak)
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    Need help and guidance on how O would work this put.Please help.

    H3PO4 and Calcium Oxide/hydroxide ?
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    (Original post by binarythoughts)
    H3PO4 and Calcium Oxide/hydroxide ?


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    It it would be really nice if you told me how to figure it out.
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    (Original post by Kadak)
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    It it would be really nice if you told me how to figure it out.

    I was first checking if it was right.

    I don't really have a method; just look at the parts of the product and try to have options for the reactants. The phosphate part of it comes from the phosphoric acid. Then you Calcium, so the most obvious bases with calcium are calcium oxide and calcium hydroxide
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    I don't get the oxidation numbers for this molecule.
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    (Original post by Kadak)
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    I don't get the oxidation numbers for this molecule.
    Uh that is actually confusing, do you have the question for that molecule so we can get a better sense of it?
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    (Original post by Disney0702)
    Uh that is actually confusing, do you have the question for that molecule so we can get a better sense of it?


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    Yes Sir.
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    I also need help with this question
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    Is this right?
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    Your definition is correct.

    Disproportionation is a specific type of redox reaction in which a species is simultaneously reduced and oxidised to form two different products.


    3Cl2(g) + 6NaOH(aq) 5NaCl(aq) + NaClO3(aq) + 3H2O(l)

    In this reaction you'll see that disproportionation has taken place as both Chlorine products has different oxidation numbers.

    In NaCl, chlorine will have a oxidation state of -1 as Na will always have a +1 oxidation state.

    In NaClO3, Chlorine will have an oxidation state of +5.
    This is because sodium will always have an oxidation state of +1, as discussed earlier, and oxygen will always have an oxidation state of -2.
    You'll see that the overall charge of NaClO3 is zero so all the oxidation numbers in each element of that molecule has to sum up to zero.

    You could see it like this:

    NaClO3 = 0

    Na + Cl + 3O = 0

    (Oxidation numbers)
    +1 +
    x + 3(-2) = 0
    x - 5 = 0
    x = + 5

    hope that helps
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    HI, can someone help me with Hydrogenation? I was on here a few days ago and I've lost my reactions and mechanisms booklet so could do with some sort of general equation if there is one? (OCR F322)
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    (Original post by Abby_W31)
    HI, can someone help me with Hydrogenation? I was on here a few days ago and I've lost my reactions and mechanisms booklet so could do with some sort of general equation if there is one? (OCR F322)


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    Hydrogenation is when you add hydrogen gas to a unsaturated alkenes, which then makes a saturated alkane.
    The pic below explains it all.
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    (Original post by Disney0702)
    Your definition is correct.

    Disproportionation is a specific type of redox reaction in which a species is simultaneously reduced and oxidised to form two different products.


    3Cl2(g) + 6NaOH(aq) 5NaCl(aq) + NaClO3(aq) + 3H2O(l)

    In this reaction you'll see that disproportionation has taken place as both Chlorine products has different oxidation numbers.

    In NaCl, chlorine will have a oxidation state of -1 as Na will always have a +1 oxidation state.

    In NaClO3, Chlorine will have an oxidation state of +5.
    This is because sodium will always have an oxidation state of +1, as discussed earlier, and oxygen will always have an oxidation state of -2.
    You'll see that the overall charge of NaClO3 is zero so all the oxidation numbers in each element of that molecule has to sum up to zero.

    You could see it like this:

    NaClO3 = 0

    Na + Cl + 3O = 0

    (Oxidation numbers)
    +1 +
    x + 3(-2) = 0
    x - 5 = 0
    x = + 5

    hope that helps


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    Omg,chlorine having an oxidation number of 5?Oh I get it.I just didn't believe that chlorine could lose 5 electrons, considering it's the electronegative one.
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    (Original post by Kadak)
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    I also need help with this question
    There was another thread where someone addressed this question.

    Check that out first and if you still do not understand it let me know.
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    (Original post by Kadak)
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    Is this right?
    Uh, what you did isn't quite right.

    You cannot have 9 electrons on the outer shells, it can only take a maximum of 8 electrons.

    I believe this is what you have to draw.



    I am not entirely sure if this is correct, please do check with a teacher.

    What exam board are you?
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    (Original post by Disney0702)
    Uh, what you did isn't quite right.

    You cannot have 9 electrons on the outer shells, it can only take a maximum of 8 electrons.

    I believe this is what you have to draw.



    I am not entirely sure if this is correct, please do check with a teacher.

    What exam board are you?
    OCR A.
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    (Original post by Kadak)
    OCR A.
    Ah right, I am AQA.

    Did you understand the other questions I helped you out with.
    And did you check the other thread, I sent you the link in the previous message.
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    (Original post by Disney0702)
    There was another thread where someone addressed this question.

    Check that out first and if you still do not understand it let me know.


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    Still not understand it 😳.
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    (Original post by Kadak)
    Posted from TSR Mobile

    Still not understand it ������.





    Hope that helps, tell me if you understand or if you need anything to be further explained.
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    Hey guys, can we all put out a couple of questions for us all to answer? Helps with revision and gets your brain working!
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    (Original post by rm_27)
    Hey guys, can we all put out a couple of questions for us all to answer? Helps with revision and gets your brain working!
    unit one or two?
 
 
 
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