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    Merry Xmas to everybody in this forum



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    from TeeEm
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    Gotta be done, after all, we are in the maths section at christmas.

    Merry Christmas everyone!

    Spoiler:
    Show

    y = \dfrac{1}{r^2}ln(\dfrac{x}{m} - sa)

    yr^2 = ln(\dfrac{x}{m} - sa)

    e^{yr^2} = \dfrac{x}{m} -sa

    e^{yr^2} +sa = \dfrac{x}{m}

    m\left( e^{yr^2} + sa\right) = x

    me^{yr^2} + msa = x

    me^{yr^2} = x - msa

    me^{rry} = x - mas
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    (Original post by TeeEm)
    Merry Xmas to everybody in this forum



    Name:  merry Xmas.jpg
Views: 100
Size:  42.1 KB


    from TeeEm
    You too.
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    (Original post by Phichi)
    Gotta be done, after all, we are in the maths section at christmas.

    Merry Christmas everyone!

    Spoiler:
    Show

    y = \dfrac{1}{r^2}ln(\dfrac{x}{m} - sa)

    yr^2 = ln(\dfrac{x}{m} - sa)

    e^{yr^2} = \dfrac{x}{m} -sa

    e^{yr^2} +sa = \dfrac{x}{m}

    m\left( e^{yr^2} + sa\right) = x

    me^{yr^2} + msa = x

    me^{yr^2} = x - msa

    me^{rry} = x - mas
    amazing spoiler!
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    (Original post by Phichi)
    Gotta be done, after all, we are in the maths section at christmas.

    Merry Christmas everyone!

    Spoiler:
    Show

    y = \dfrac{1}{r^2}ln(\dfrac{x}{m} - sa)

    yr^2 = ln(\dfrac{x}{m} - sa)

    e^{yr^2} = \dfrac{x}{m} -sa

    e^{yr^2} +sa = \dfrac{x}{m}

    m\left( e^{yr^2} + sa\right) = x

    me^{yr^2} + msa = x

    me^{yr^2} = x - msa

    me^{rry} = x - mas
    Beat me to it!
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    Merry Christmas to all at forum 38 !!

    I hope you enjoy your festive functions

    :getmecoat:

    :merryxmas:
    • Community Assistant
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    Merry Christmas to all.

    I'd like to say thank you to everyone on this forum who regularly help out people (especially the people that have the patience to help me!)
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    Merry Christmas everyone!
 
 
 
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