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    (Original post by JSaunders9)
    Can't use the lens equation because there was no image only two objects
    Think of it like this: the eye of that person can handle curvature of -0.8D, so when something has a curvature of -4D, you need to add on 3.2D to correct for the eye.
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    (Original post by HennersPD)
    Got this too as 1/u is -0.8
    Kind of upset though I think I put 3.2 on the actual paper
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    (Original post by Wolfea)
    Think of it like this: the eye of that person can handle curvature of -0.8D, so when something has a curvature of -4D, you need to add on 3.2D to correct for the eye.
    yeah taht was what I put on my paper and I am really confused :confused: as to what I should have done. I put down 3.2 with that reasoning but now i have my doubts i think its 4.8
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    (Original post by CancerousProblem)
    yeah taht was what I put on my paper and I am really confused :confused: as to what I should have done. I put down 3.2 with that reasoning but now i have my doubts i think its 4.8
    Sorry what was the reasoning behind 4.8? I can't think of any.
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    what did people get for the ratio of resistivities, sensitivity and average current/charge calculations with the voltage temperature graph?
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    (Original post by CancerousProblem)
    yeah taht was what I put on my paper and I am really confused :confused: as to what I should have done. I put down 3.2 with that reasoning but now i have my doubts i think its 4.8
    i got -3.2 to begin with but crossed it out and put 4.8, i think either way there will be one mark for using the equation, even if our answer was wrong
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    (Original post by jack0997)
    what did people get for the ratio of resistivities, sensitivity and average current/charge calculations with the voltage temperature graph?

    For the ratio I think I got 6.6..that's about as much as I can remember
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    (Original post by Mutleybm1996)
    100 and 10khz so 9900


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    I got that too
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    (Original post by HennersPD)
    Did you get D, C, B for the 3 graphs?
    I think i put D A B, can't fully recall sorry. My brain still feels like its been raped
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    (Original post by Mutleybm1996)
    Could be have used either resistance for the resistivity one?
    Most in my class used 3.14
    Some used the 200 and something


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    I just put the assumed resistance as 2 ohms, i didnt think you needed to use a previous value as the question said to state assumptions
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    (Original post by IIEquinoxII)
    I just put the assumed resistance as 2 ohms, i didnt think you needed to use a previous value as the question said to state assumptions
    Do you mean you assume the value of the pd at 35mA is the value for 20 degrees C?
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    (Original post by IIEquinoxII)
    I just put the assumed resistance as 2 ohms, i didnt think you needed to use a previous value as the question said to state assumptions
    Is this to work out the length? I think I used the resistance at the lowest voltage that we had to work out in table
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    What do everyone think they got btw and please no one say above 50
    • Thread Starter
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    (Original post by Picton2727)
    Is this to work out the length? I think I used the resistance at the lowest voltage that we had to work out in table
    Yeah


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    i put 4.8D by using the equation 1/u+1/f=1/u

    So i just did -0.8+P=4

    so P=4.8D
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    What did you get for the length of the tungsten wire?
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    (Original post by Picton2727)
    Is this to work out the length? I think I used the resistance at the lowest voltage that we had to work out in table
    Yeah, i just picked 2 ohms as it seemed like a sensible enough number
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    (Original post by CancerousProblem)
    What did you get for the length of the tungsten wire?
    0.018m?
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    (Original post by CancerousProblem)
    What did you get for the length of the tungsten wire?
    about 0.001 meter?
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    (Original post by jack0997)
    0.018m?
    I got that too!

    did you use the 3.14 ohm resistance then?
 
 
 
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