Join TSR now and get all your revision questions answeredSign up now

OCR PHYSICS B G494~ 11th June 2015 AM ~ A2 Physics Watch

    Offline

    1
    ReputationRep:
    (Original post by ExMus)
    So is there an unofficial mark scheme about? Feel like I got 51 marks. Not really happy about that.
    Uploaded previously, but here it is again.
    Attached Images
  1. File Type: pdf g494.pdf (29.1 KB, 771 views)
    • Thread Starter
    Offline

    3
    ReputationRep:
    (Original post by Iridann)
    It was V grav, not F
    Which did you put?


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by Greating)
    Uploaded previously, but here it is again.
    Thanks a lot. This doesn't tell us the marks though :/
    Offline

    3
    ReputationRep:
    (Original post by Mutleybm1996)
    Which did you put?


    Posted from TSR Mobile
    I put B
    Offline

    2
    ReputationRep:
    I think I missed 2 questions. Idk how...easy questions too
    Offline

    3
    ReputationRep:
    (Original post by Greating)
    Uploaded previously, but here it is again.
    I did Q3 differently: did 42/18 = 2.3 for gamma factor and simply divided the speed of light by this to get v as 1.3*10^8 ms-1 - is this wrong? :/ thought i got it correct :/
    Offline

    2
    ReputationRep:
    It's unfortunately not correct but don't lose sleep over it. 2 marks right?
    Offline

    3
    ReputationRep:
    (Original post by ExMus)
    It's unfortunately not correct but don't lose sleep over it. 2 marks right?
    yeah think so, it should matter! what grade do you think 45 on this paper will be? :/
    • Thread Starter
    Offline

    3
    ReputationRep:
    Would more precise instruments get me the mark?


    Posted from TSR Mobile
    • Thread Starter
    Offline

    3
    ReputationRep:
    (Original post by HennersPD)
    yeah think so, it should matter! what grade do you think 45 on this paper will be? :/
    A


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    Ok thanks, how'd you think you did?
    • Thread Starter
    Offline

    3
    ReputationRep:
    (Original post by HennersPD)
    Ok thanks, how'd you think you did?
    Possibly an A...depends on how they mark some of the wordy ones


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by Mutleybm1996)
    Possibly an A...depends on how they mark some of the wordy ones


    Posted from TSR Mobile
    ah yeah that's true how about f324 chemistry, what'd you think 44/60 on that would be? :/ how'd did you find it? what'd you need for uni?
    Offline

    1
    ReputationRep:
    (Original post by HennersPD)
    I did Q3 differently: did 42/18 = 2.3 for gamma factor and simply divided the speed of light by this to get v as 1.3*10^8 ms-1 - is this wrong? :/ thought i got it correct :/
    Yeah that's wrong, you had to let gamma=2.3rec and rearrange to find v, the value was like 2.7x10^8 ms^-1 (2sgf)
    Offline

    3
    ReputationRep:
    (Original post by asdfghi)
    Yeah that's wrong, you had to let gamma=2.3rec and rearrange to find v, the value was like 2.7x10^8 ms^-1 (2sgf)
    Ah ok whatd you think 44/60 will be on this exam?
    Offline

    0
    ReputationRep:
    Was the Boltzmann factor question e^(-epsilon/kt) or was it e^(+epsilon/kt)?


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by Alanrowe)
    Was the Boltzmann factor question e^(-epsilon/kt) or was it e^(+epsilon/kt)?


    Posted from TSR Mobile
    Negative.
    Offline

    0
    ReputationRep:
    Yay!!


    Posted from TSR Mobile
    Offline

    0
    ReputationRep:
    So it was like this:

    1/10=(e^(-epsilon/300k))/(e^-epsilon/400k))

    Giving

    1/10=e^(epsilon(-1/300k+1/400k))

    Then

    ln(0.1)=epsilon(-1/300k+1/400k)

    So

    Epsilon =l 3.86x10^-20J


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by Alanrowe)
    So it was like this:

    1/10=(e^(-epsilon/300k))/(e^-epsilon/400k))

    Giving

    1/10=e^(epsilon(-1/300k+1/400k))

    Then

    ln(0.1)=epsilon(-1/300k+1/400k)

    So

    Epsilon =l 3.86x10^-20J


    Posted from TSR Mobile
    Bang on bro.
 
 
 
Poll
Which web browser do you use?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.