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OCR PHYSICS B G495~ 18th June 2015 AM ~ A2 Physics watch

1. (Original post by urz13)
Can anyone help with this? Cheers

Use the relationship Bqr= energy of particle/speed of light

to show that the unit of magnetic field strength, the Tesla, is equal to N A^-1 m^-1
Use F=mv^2r^-1 and Use that C = As and you should get it
2. (Original post by urz13)
Can anyone help with this? Cheers

Use the relationship Bqr= energy of particle/speed of light

to show that the unit of magnetic field strength, the Tesla, is equal to N A^-1 m^-1

There

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3. (Original post by vietnamfam)
Use F=mv^2r^-1 and Use that C = As^-1 and you should get it
I thought a Coulomb was As...not As^-1

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4. (Original post by Mutleybm1996)
I thought a Coulomb was As...not As^-1

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5. (Original post by vietnamfam)

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6. (Original post by vietnamfam)
Use F=mv^2r^-1 and Use that C = As and you should get it

Easiest way

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7. (Original post by Mutleybm1996)
Attachment 430763

Gone wrong somewhere

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Well if you have just B on one side and break it into units then
B=([J])/([ms^(-1) ][C][m])
Then you know that [A]=([C])/([s]) (from formula book) so,
B=([J])/([m][A][m])
Then you know that [N]=([J])/([m]) (work done=energy=force x distance ) so,
B=([N])/([m][A])
Sorry it is messy if you don't understand i can write it out
8. C
(Original post by qivo)
Well if you have just B on one side and break it into units then
B=([J])/([ms^(-1) ][C][m])
Then you know that [A]=([C])/([s]) (from formula book) so,
B=([J])/([m][A][m])
Then you know that [N]=([J])/([m]) (work done=energy=force x distance ) so,
B=([N])/([m][A])
Sorry it is messy if you don't understand i can write it out
Thanks, I've done it two ways ^

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9. Has anyone got the June 2014 g495 paper?
10. (Original post by Mars256)
Has anyone got the June 2014 g495 paper?
http://moodle.flintshire.gov.uk/hhs/...iew.php?id=780

All the papers are on here, including june 2014
11. Hi! There's this question I just don't understand and I don't even understand the mark scheme!!!
Can somebody please explain it to me, the question and the mark scheme are attached.

Thanks!

12. Question re Flemming's Left Hand Rule:
So the second finger shows direction of current - is this of conventional current (i.e. the same direction protons would flow) or the direction of electron flow?
13. (Original post by yohollyyo)
Question re Flemming's Left Hand Rule:
So the second finger shows direction of current - is this of conventional current (i.e. the same direction protons would flow) or the direction of electron flow?
electron flow
14. (Original post by falconinni)
http://moodle.flintshire.gov.uk/hhs/...iew.php?id=780

All the papers are on here, including june 2014
Thank very much!!!
15. (Original post by yohollyyo)
Question re Flemming's Left Hand Rule:
So the second finger shows direction of current - is this of conventional current (i.e. the same direction protons would flow) or the direction of electron flow?
It's conventional current.
16. (Original post by Iridann)
It's conventional current.
but what about when you use the left hand rule on a moving electron?
17. (Original post by maxAmain)
but what about when you use the left hand rule on a moving electron?
No the rule only applies to conventional current.
18. (Original post by Mutleybm1996)
I hear G484 was horrible this year
With even top students barely scraping 40

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Hm, the people from my class who were resitting said it was easier than the paper last year, but then again it was like half marks for an A in that paper
19. (Original post by maxAmain)
but what about when you use the left hand rule on a moving electron?
Just do the current opposite way around
20. (Original post by Tibbz2)
Hm, the people from my class who were resitting said it was easier than the paper last year, but then again it was like half marks for an A in that paper
Are you a year 14?

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