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    Hi I have attempted question 5 and also rechecked my work but I can't figure out where I've gone wrong. My answer is 278/27 but the book says 270/8

    I have attached my working out

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    My working out

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    (Original post by the_googly)
    My working out

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    You are correct: 278/27.
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    (Original post by Smaug123)
    You are correct: 278/27.
    Cool so the book is wrong
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    (Original post by the_googly)
    Cool so the book is wrong
    So it would appear.
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    Hi on question 4b I'm stuck on integrating x/x+1 (which I end up with in working out). Please help

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    The question

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    (Original post by the_googly)
    Hi on question 4b I'm stuck on integrating x/x+1 (which I end up with in working out). Please help

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    \displaystyle \frac{x}{x+1}=\frac{(x+1)-1}{x+1}=1-\frac{1}{x+1}
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    You'd actually have been better advised to use the correct form of partial fractions (or perform the FULL division) at outset.

    \displaystyle \frac{x(2x+1)}{x+1}=Ax+B+\frac{C  }{x+1}
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    (Original post by Mr M)
    You'd actually have been better advised to use the correct form of partial fractions (or perform the division) at outset.

    \displaystyle \frac{x(2x+1)}{x+1}=Ax+B+\frac{C  }{x+1}
    I have not seen anything like the above in my book:confused:
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    (Original post by the_googly)
    I have not seen anything like the above in my book:confused:
    Possibly not but you certainly know how to divide a quadratic by a linear term.

    The form I provided is correct as the quotient must be linear.
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    That's what I've been given in the book. From My understanding when the fraction is in proper you use polynomial long division?

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    (Original post by the_googly)
    That's what I've been given in the book. From My understanding when the fraction is in proper you use polynomial long division?

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    Improper.

    Yes that's what I just did.

    Edit: You do realise you didn't complete your long division?
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    (Original post by Mr M)
    Improper.

    Yes that's what I just did.
    Didn't I do that?
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    (Original post by Mr M)
    Improper.

    Yes that's what I just did.

    Edit: You do realise you didn't complete your long division?
    No I don't lol
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    (Original post by the_googly)
    Didn't I do that?
    No you didn't complete the division. You left yourself with another improper fraction.

    x/(x+1) is improper because the numerator is not of lower degree than the denominator.
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    How about now?

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    (Original post by the_googly)
    How about now?

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    Nope.

    0 - - 1 \neq -1
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    (Original post by Mr M)
    Nope.

    0 - - 1 \neq -1
    Ok thanks.
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    Also struggling on question 3A lol

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