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    The only thing I know I should do is integrate the dy/dx equation, but then I don't really know what to do afterwards :/

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    I think you've uploaded the wrong image. The stuff you've typed does not match the image(text is integration, image is surds).
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    (Original post by morgan8002)
    I think you've uploaded the wrong image. The stuff you've typed does not match the image(text is integration, image is surds).
    Oops sorry, it's fixed now
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    To find the equation of a tangent, you need to find the gradient of the tangent and have a point on the line. Does this help?


    The first step is to find the equation of the tangent. Integrating comes later in the question.
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    (Original post by morgan8002)
    To find the equation of a tangent, you need to find the gradient of the tangent and have a point on the line. Does this help?


    The first step is to find the equation of the tangent. Integrating comes later in the question.
    I managed to get the gradient but I didn't know what the y coordinate would be so I could form and equation?
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    (Original post by creativebuzz)
    I managed to get the gradient but I didn't know what the y coordinate would be so I could form and equation?
    The question says that the tangent passes through the origin, so you can use (0, 0) as a point on the tangent.

    You need to use all of the information that the question gives you, because they will never give you more information than you need.
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    F'(x) = 3(x)^2 - 4x -1

    F(x) (which is equal to y) is just the integral of f'(x)

    Then set up an equation involving y and sub in x=2 to get the y value innit :yes:

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    (Original post by Fermions)
    F'(x) = 3(x)^2 - 4x -1

    F(x) (which is equal to y) is just the integral of f'(x)

    Then set up an equation involving y and sub in x=2 to get the y value innit :yes:

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    You are left with an arbitrary constant of integration, so you have to use the other information given in the question to find the value of the constant and thus the equation of the line.
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    (Original post by morgan8002)
    You are left with an arbitrary constant of integration, so you have to use the other information given in the question to find the value of the constant and thus the equation of the line.
    Dayuum

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    (Original post by Fermions)
    Dayuum

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    That is exactly ​where I got stuck, I then thought of using the (0,0) coordinates with that method but that didn't give me the right answer and I don't understand why it didn't.. :/
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    (Original post by creativebuzz)
    That is exactly ​where I got stuck
    So have you managed to find the equation of the tangent?
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    (Original post by morgan8002)
    So have you managed to find the equation of the tangent?
    Well my initial method was to
    1) find gradient = 3

    2) then the eq of the tangent: y - 0 = 3(x -0)
    to give me y=3x

    but I wasn't confident in my answer :/
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    To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.

    Hope this helps

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    (Original post by creativebuzz)
    Well my initial method was to
    1) find gradient = 3

    2) then the eq of the tangent: y - 0 = 3(x -0)
    to give me y=3x

    but I wasn't confident in my answer :/
    Yes that is correct. Now use this to find the y coordinate at x = 2, then use this point to find an equation of the curve.
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    (Original post by ImNervous)
    To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.

    Hope this helps

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    Yes, then substitute this constant into the equation of the curve to find the final answer.
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    (Original post by ImNervous)
    To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.

    Hope this helps

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    Brilliant! Positive rating given for thanks
 
 
 
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