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# AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread] watch

1. That capacitor question annoyed me so much. I was internally raging. I worked out that the current dips 1/400 of a square.

It still annoys me now. Here's a graph of a capacitor discharging, what happens when we times the resistance by 2000?

Now try and draw that on the same axis.
B******s
2. First 5 MC I got CAADA but i'm sure the first is wrong

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3. number of rotations i got 2????
4. (Original post by Fred Cantoni)
Any one else get A A A as the first three MC?

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No, D A A
D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
force unit is Newtons
5. (Original post by Klaxoii)
First 5 MC I got CAADA but i'm sure the first is wrong

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6. This http://youtu.be/HV4FNXt1F6Y shows that without ring has heavier damping

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7. (Original post by cudders96)
Anyone else notice on the current graph question that the first resistance was 150Ω, but the second was 300KΩ? Think it was probably a typo on AQA's behalf, because the resulting graph would have to start with initial current 2000x lower than the original graph.
Was it steeper gradient with less area under graph, I forgot to adjust my current
8. Bit of an odd paper-personally found MC easier than the written paper...
Waiting for UNNOFICIAL markscheme .... Hopefully should have one by this evening?
9. (Original post by Ilovemaths96)
number of rotations i got 2????
Same, is that for circular motion part?
10. (Original post by Ilovemaths96)
number of rotations i got 2????

I got that too! Thought it was wrong cuz everyone says different things lol
11. (Original post by davidharris96)
No, D A A
D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
force unit is Newtons
Oh I think I put newtons... Maybe I didn't put A...

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12. (Original post by Cmog)
Was it steeper gradient with less area under graph, I forgot to adjust my current
It was a typo. You physically couldn't draw the graph as the current was so small.
13. First question I put the unit was equal to acceleration ?
14. (Original post by Cmog)
Was it steeper gradient with less area under graph, I forgot to adjust my current
Shallower gradient? the area should be the same as there was the same charge in the capacitor?

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15. This was my order for multiple choice but some are definitely wrong

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16. What the **** was that
17. (Original post by michaelotty)
This http://youtu.be/HV4FNXt1F6Y shows that without ring has heavier damping

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Yep, so damping was less when mass was added
18. rate of change of momentum is m(v-u)/t units are ms-1/s which makes ms-2 so acceleration surely
19. (Original post by Qwerty1996)
This was my order for multiple choice but some are definitely wrong

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I got the same as you except for 2
20. (Original post by Kkdhaliwal)
First question I put the unit was equal to acceleration ?
Rate of change of momentum =mv/t

Therefore unit is kg * ms^-1 * s^-1 = Kgms^-2
This is equaivalent to mg (Kg * ms^-2)

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