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AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread] Watch

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    That capacitor question annoyed me so much. I was internally raging. I worked out that the current dips 1/400 of a square.

    It still annoys me now. Here's a graph of a capacitor discharging, what happens when we times the resistance by 2000?

    Now try and draw that on the same axis.
    B******s
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    First 5 MC I got CAADA but i'm sure the first is wrong


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    number of rotations i got 2????
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    (Original post by Fred Cantoni)
    Any one else get A A A as the first three MC?


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    No, D A A
    D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
    force unit is Newtons
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    (Original post by Klaxoii)
    First 5 MC I got CAADA but i'm sure the first is wrong


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    Think I got AAADD :/


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    This http://youtu.be/HV4FNXt1F6Y shows that without ring has heavier damping


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    (Original post by cudders96)
    Anyone else notice on the current graph question that the first resistance was 150Ω, but the second was 300KΩ? Think it was probably a typo on AQA's behalf, because the resulting graph would have to start with initial current 2000x lower than the original graph.
    Was it steeper gradient with less area under graph, I forgot to adjust my current
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    Bit of an odd paper-personally found MC easier than the written paper...
    Waiting for UNNOFICIAL markscheme .... Hopefully should have one by this evening?
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    (Original post by Ilovemaths96)
    number of rotations i got 2????
    Same, is that for circular motion part?
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    (Original post by Ilovemaths96)
    number of rotations i got 2????

    I got that too! Thought it was wrong cuz everyone says different things lol
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    (Original post by davidharris96)
    No, D A A
    D was the correct answer as Rate of change of momentum is F = (mv-mu)/t
    force unit is Newtons
    Oh I think I put newtons... Maybe I didn't put A...


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    (Original post by Cmog)
    Was it steeper gradient with less area under graph, I forgot to adjust my current
    It was a typo. You physically couldn't draw the graph as the current was so small.
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    First question I put the unit was equal to acceleration ?
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    (Original post by Cmog)
    Was it steeper gradient with less area under graph, I forgot to adjust my current
    Shallower gradient? the area should be the same as there was the same charge in the capacitor?


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    This was my order for multiple choice but some are definitely wrong

    DAADDBCBABACDCACCBBABACBD



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    What the **** was that
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    (Original post by michaelotty)
    This http://youtu.be/HV4FNXt1F6Y shows that without ring has heavier damping


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    Yep, so damping was less when mass was added
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    rate of change of momentum is m(v-u)/t units are ms-1/s which makes ms-2 so acceleration surely
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    (Original post by Qwerty1996)
    This was my order for multiple choice but some are definitely wrong

    DAADDBCBABACDCACCBBABACBD



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    I got the same as you except for 2
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    (Original post by Kkdhaliwal)
    First question I put the unit was equal to acceleration ?
    Rate of change of momentum =mv/t

    Therefore unit is kg * ms^-1 * s^-1 = Kgms^-2
    This is equaivalent to mg (Kg * ms^-2)
 
 
 
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