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# AQA Physics PHYA4 - Thursday 11th June 2015 [Exam Discussion Thread] watch

1. Yep, BAN/T
2. (Original post by muhts)
Yep, BAN/T
I see my mistake now thanks
3. Any ideas on grade boundaries ?
4. What was the appropriate number of sig fig question? I feel like I didn't notice this
5. (Original post by smoothER)
What was the appropriate number of sig fig question? I feel like I didn't notice this
The capacitor and pulling the mass up question
6. (Original post by aprocrastinator)
The capacitor and pulling the mass up question
Ahh how many sf was it? Shame I didn't notice. I recall putting 2 or 3. Thank you
7. If you got 4.8 for emf induced I think you accidently multiplied by 40 coils twice
8. (Original post by DysonCube)
No, the one in section B with the graph where it asks you to work out the field strength at 0.4m. I got 1875Vm-1 but the MS on here says 1560Vm-1.
i got 1875 aswell. I still think I'm right lol

basically - you find the corresponding value for 2.5 on the graph since 1/0.4 is 2.5.

which is -750V then you use the potential gradient equation which is valid because the same rules from grav field apply to electric fields.

E = V/r

so its 750 x 2.5 = 1875. Makes sence! Not sure where 1560 came from lol.
9. Yh
It was 1875
10. (Original post by Kennethm)
i got 1875 aswell. I still think I'm right lol

basically - you find the corresponding value for 2.5 on the graph since 1/0.4 is 2.5.

which is -750V then you use the potential gradient equation which is valid because the same rules from grav field apply to electric fields.

E = V/r

so its 750 x 2.5 = 1875. Makes sence! Not sure where 1560 came from lol.
(Original post by Boton)
Yh
It was 1875
I think you both accidentally used 750V in your calculations. The corresponding potential at r=0.4m (hence at 1/r = 2.5) was 625V.

As such, you do E=v/r

So E = 625/0.4

= 1562.5 Vm^-1

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11. Plus if you use the standard field strength equation you get 1560 too
12. (Original post by CD223)
I think you both accidentally used 750V in your calculations. The corresponding potential at r=0.4m (hence at 1/r = 2.5) was 625V.

As such, you do E=v/r

So E = 625/0.4

= 1562.5 Vm^-1

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ohhh rip pretty sure thats like 1 mark lost tho - correct equation used blah blah
13. (Original post by Kennethm)
ohhh rip pretty sure thats like 1 mark lost tho - correct equation used blah blah
Not sure how the written will go to be honest. Praying for low boundaries as I made stupid mistakes in section B.

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14. (Original post by xela238)
What question are you referencing?

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the last one with the 6 marker
15. Anyone got a copy of the MC paper?
16. HAVE YOU GUYS SEEN THIS
http://www.bbc.co.uk/news/education-33094306

AQA apologises for the question mistake in the exam 😮
17. (Original post by Sbarron)
Anyone got a copy of the MC paper?
Hopefully one will be uploaded later today.

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18. What do u guys think the boundaries will be for an a*? Also has anyone done the empa this yr... How did u guys find it?
19. (Original post by QueNNch)
HAVE YOU GUYS SEEN THIS
http://www.bbc.co.uk/news/education-33094306

AQA apologises for the question mistake in the exam 😮
Aqa better disregard the question because imagine how hard we'd get penalised if we didn't include a 'kilo' in our answer. When I did the paper I thought that one resistor being 2000 times more resistive than the other was a bit strange. Fair is fair so the 3 marks should just be taken from the paper.

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20. if we got that question right, where AQA make a mistake, would that be worse for us because then it nullifies our correct answer?

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