Join TSR now and get all your revision questions answeredSign up now

AQA Physics PHYA5 - Thursday 18th June 2015 [Exam Discussion Thread] Watch

    Offline

    0
    ReputationRep:
    (Original post by Tomh97)
    1u = 1.661*10-27
    1u= 931.5MeV
    This is on the data sheet so no need to worry!
    Offline

    2
    ReputationRep:
    Ratio of 2:1
    Offline

    3
    ReputationRep:
    (Original post by saad97)
    June 14 paper, calculating mass lost on 1biii) why do you multiply binding energy by 1.6x10^-1? Where did they get that number from?
    energy released is Mev*1.60*10-19*1.0*10^6 because mega electron volts

    191*1.60*10-19*1.0*10^6= 3.06*10-11
    E=mc^2
    m=E/c^2
    m= 3.06*10-11/ (3.0*10^8)^2
    = 3.4*10^-28

    is that alright?
    Offline

    2
    ReputationRep:
    (Original post by Mai.H)
    energy released is Mev*1.60*10-19*1.0*10^6 because mega electron volts

    191*1.60*10-19*1.0*10^6= 3.06*10-11
    E=mc^2
    m=E/c^2
    m= 3.06*10-11/ (3.0*10^8)^2
    = 3.4*10^-28

    is that alright?
    Ah yeah makes sense now thanks
    Offline

    0
    ReputationRep:
    anyone doing turning points?
    Offline

    0
    ReputationRep:
    How likely is the derivation of the ideal gas law to come up?
    Offline

    2
    ReputationRep:
    Very likely, don't think I've seen a question come up in it before
    Offline

    2
    ReputationRep:
    Yes
    Offline

    3
    ReputationRep:
    (Original post by dannyoboy007)
    How likely is the derivation of the ideal gas law to come up?
    0.
    Offline

    3
    ReputationRep:
    Why am I getting up at 2am to revise for an exam I'm FAILING!!??
    Offline

    3
    ReputationRep:
    (Original post by ubisoft)
    0.
    With a paper written last minute?? Likely
    Offline

    3
    ReputationRep:
    Explain the electron beam experiment in key bullet points
    Offline

    2
    ReputationRep:
    Name:  image.jpg
Views: 99
Size:  524.1 KBPlease can you help me with 2b II thanks ☺️
    Offline

    0
    ReputationRep:
    It's safer to multiply by 931.4 MeV, plus thats what the data sheet says, good luck

    (Original post by MrKlaus)
    does anyone know if you times the atomic mass unit by 931 or 931.5 to give the energy in MeV?
    Offline

    2
    ReputationRep:
    (Original post by Ilovemaths96)
    June 10 - nuclear reactors and fission
    June 11 - how a gas exerts pressure
    June 12 - nuclear radii
    June 13 - verifying types of radiation emitted by a source

    June 14 - nuclear waste

    June 15 - maybe something about gases?
    Thank you so much. And yeah exactly what I think, the laws maybe and what the conditions are for an ideal gas
    Offline

    3
    ReputationRep:
    (Original post by Lizzieee4)
    Thank you so much. And yeah exactly what I think, the laws maybe and what the conditions are for an ideal gas
    What would you put for the conditions for an ideal gas? The kinetic theory assumptions?
    Offline

    0
    ReputationRep:
    any idea what sorta definitions they might ask for?
    Offline

    0
    ReputationRep:
    anyone got tips on how to approach questions to do with specific heat capacity and specific latent heat? e.g. the one on the june 2014 paper
    Offline

    2
    ReputationRep:
    (Original post by Mai.H)
    What would you put for the conditions for an ideal gas? The kinetic theory assumptions?
    Yeah, sorry that's what I meant hahaha. Just slowly loosing it after having biology yesterday....
    Offline

    2
    ReputationRep:
    (Original post by Sbarron)
    With a paper written last minute?? Likely
    I thought the physics ones weren't stolen though
 
 
 
Poll
Which web browser do you use?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.