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# AQA Physics PHYA5 - Thursday 18th June 2015 [Exam Discussion Thread] watch

1. (Original post by a.a.k)

Yeah u find the number if moles then divide by avagadro constant to get number of particles or in this case number of molecules

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oh ok thanks, why cant you use the normal formula with N?
2. Hi ... I don't get why you do 600/0.35 instead of 600 * 0.35 ??
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3. (Original post by imyimy)
oh ok thanks, why cant you use the normal formula with N?
I dont know tbh i dont want to give u wrong advice

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4. (Original post by imyimy)
oh ok thanks, why cant you use the normal formula with N?
You got the right answer it is +21
So you CAN use pV=NkT
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5. Hi I am really stuck on this question... Any help would be appreciated
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6. (Original post by sykik)
Hi ... I don't get why you do 600/0.35 instead of 600 * 0.35 ??
It should be 600*0.35

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7. (Original post by sykik)
Hi ... I don't get why you do 600/0.35 instead of 600 * 0.35 ??
Hmm, I think it's because of this:

The Power output is 6000MW, but this is only 35% of the overall energy supplied by the fuel rods, so dividing by 0.35 gives you 100% of the energy supplied by the fuel rods,, I guess from then you can work out the decrease in mass (based on part a? idk..)
8. 1.14x10^-2 kg
9. (Original post by Cosmocos)
Hmm, I think it's because of this:

The Power output is 6000MW, but this is only 35% of the overall energy supplied by the fuel rods, so dividing by 0.35 gives you 100% of the energy supplied by the fuel rods,, I guess from then you can work out the decrease in mass (based on part a? idk..)
doesn't 600/0.35 give u the input power?
10. (Original post by sykik)
1.14x10^-2 kg
Close i got 1.41x10^-3 kg

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11. Actually its not close enough

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12. (Original post by sykik)
doesn't 600/0.35 give u the input power?
Isn't the power input what is supplied by the fuel rods? lol I;m not sure tbh
13. [QUOTE=a.a.k;56386187]Close i got 1.41x10^-3 kg

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14. This is what i got

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15. (Original post by sykik)
Hi I am really stuck on this question... Any help would be appreciated
After probably doing it the longest way possible. I got a mass of 80623 kg...lol
16. 600MW is only elextrical energy which is only 35% other 75% energy is wasted whixh you need to take in account so you need to fins 100% energy by 600x100/35

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17. (Original post by Cosmocos)
After probably doing it the longest way possible. I got a mass of 80623 kg...lol
That might be mass of crude oil

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18. Hey guys will the formula for closest approach of a scattered particle be given in the exam??
19. (Original post by santiago_carmelo)
Hey guys will the formula for closest approach of a scattered particle be given in the exam??

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20. Tomato tomato is it given? or do i have to memorise the thing
(Original post by a.a.k)

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