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    for part (b) & (c), how do I covert the given equations into the standard form (cos I can only find the centre, foci etc after converting it into the standard form yeah...)? Ive tried something, but can't figure it out really...

    Thank you!

    Sid
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    You'll need to do some dividing through, and completing the square.
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    You should get a out as 3root3 and b out as 2root3 for the second q I think.

    Might have made a mistake two secs
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    (Original post by L'Evil Fish)
    You should get a out as 3root3 and b out as 2root3 for the second q I think.
    I'll be able to do (c) if I know how to do (b). In (b), I can manage to get the y part in the standard form but then I'm not sure how to manipulate the 4x^2 part without disturbing the standardised y part, if that makes sense...


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    (Original post by Sidhant Shivram)
    I'll be able to do (c) if I know how to do (b). In (b), I can manage to get the y part in the standard form but then I'm not sure how to manipulate the 4x^2 part without disturbing the standardised y part, if that makes sense...


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    Right so you have

    4x^2 + 9y^2 - 18y = 27
    4x^2 + 9(y^2-2y) = 27
    4x^2 + 9((y-1)^2 - 1) = 27
    4x^2 + 9(y-1)^2 = 36

    Divide through by 36 and you'll have it in the right form

    Giving a =3 and b = 2 not what I said before
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    Oh no! I got it. It's easier than i thought. Thank you! Sorry for the hassle, L'evil Fish!
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    (Original post by Sidhant Shivram)
    Oh no! I got it. It's easier than i thought. Thank you! Sorry for the hassle, L'evil Fish!
    Np

    Its quite an easy topic with the help of the formula booklet :lol:
 
 
 
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