Thanks. I am sure i am sure i could be able to do those if there arent any big numbers involved.(Original post by Chittesh14)
I hope you understand this:
Make x the same in both equations by finding a number that has 3 and 4 as a factor, in this case 12.
Subtract both equations, so 12x - 12x becomes 0x, because of the two minus signs, 20y - -6y becomes 20y + 6y = 26y.
Also, 76 - -54 becomes 76 + 54 = 130. Therefore, 26y = 130.
130 / 26 is 5 = y.
Substitute the value of y into the equation to find x.
3x + 5y(25) = 19.
19 - 25 = -6 = 3x
Therefore, x = -6 / 3 = -2.
Finally, x = -2 and y = 5
Took me ages to type this, but hope it helps, typing on the iPad sucks :/
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GCSE simultaneous equation help please watch
- Thread Starter
- 30-12-2014 22:58