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Official Edexcel S3 thread Wednesday 20 May 2015 Morning [6691] Watch

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    For question 2... i thought it was a 5% sig lvl.. stating the critical value to be 1.6449.... therefore accept ho? I got the right test statistic.... How many marks will I loose?
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    (Original post by 13 1 20 8 42)
    I'm in a similar boat
    60 will probably be around the A boundary, 70 certainly above that so you still have over 80% overall
    And you need 90% across any 3 A2 modules (so 270/300 marks, not 90% in each module) as well as the overall 80%; all your remaining modules are A2
    You are still well on course for an a*
    Any three or does it need to include fp2-3 ?
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    (Original post by TabulaSmaragdina)
    Lol I meant % i.e. 60% and 70%.
    Oops
    Yeah assuming those worst case scenarios you need a total of 350 UMS out of the remaining 400
    And as said 270/300 across three of them
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    Thanks!
    (Original post by 13 1 20 8 42)
    Oops
    Yeah assuming those worst case scenarios you need a total of 350 UMS out of the remaining 400
    And as said 270/300 across three of them
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    (Original post by xyzmaster)
    Any three or does it need to include fp2-3 ?
    I am almost certain it is any three
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    (Original post by 13 1 20 8 42)
    I am almost certain it is any three
    That sounds good to me. Thanks
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    Either FP2 or FP3 is mandatory (like FP1) BUT it doesn't need to be one of the 3 A* modules, e.g. You might have FP1 M1 FP2 and then 3 A* modules e.g. S3 S2 M2.
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    (Original post by Mutleybm1996)
    So would we get 0 marks for the table if we wrote 25 25 25 25 just marks for the conclusion, degrees of freedom and hypothesis?
    None whatsoever for the table?
    My teachers said we would only lose about 3-4 marks due to a final accuracy Mark and one or two for the expected frequencies, the test statistics should all follow through from our answers


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    Anyone?


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    I got 66 in this. A* by any chance?
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    (Original post by Braddy16)
    Either FP2 or FP3 is mandatory (like FP1) BUT it doesn't need to be one of the 3 A* modules, e.g. You might have FP1 M1 FP2 and then 3 A* modules e.g. S3 S2 M2.
    Ah right. That's great ,
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    (Original post by Mutleybm1996)
    Anyone?


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    I think one mark hypothesis. One mark for the critical value
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    For question 6a
    I stupidly did the normal distrbution for goodness of fit
    How many marks would pick up?
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    (Original post by Rajsab)
    For question 6a
    I stupidly did the normal distrbution for goodness of fit
    How many marks would pick up?
    I don't think you'll get any
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    (Original post by xyzmaster)
    I think one mark hypothesis. One mark for the critical value
    7 for the table seems really harsh


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    (Original post by TheRealBossBoom)
    I got 66 in this. A* by any chance?
    Think I may have got this (though it's a positive estimate)

    If you look at the years since a* was introduced it has never wavered from between 68 and 69

    However, this is harder than any of the previous papers including IAL and R

    I would be tempted to say 67 but having seen how many were stumped by 4d who knows, could be like 64-66ish

    Luckily though a high a can still serve you given that 90% across three modules rather than 90% individually in each is what's needed overall
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    (Original post by Mutleybm1996)
    7 for the table seems really harsh


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    I like to use lower limit more often so as to keep working to do even better for the coming papers
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    how did people calculate r and s for 6 b) ?
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    (Original post by Mutleybm1996)
    7 for the table seems really harsh


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    i think you'll lose 1 for hypothesis, 2 for accuracy, +2/3 for method maybe? idk im guessing you'll might lose 4/5 marks? try looking at prev mark schemes and see how they mark!
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    I did normal disturbuution for 6a
    How manny marks would i pick up?
    Woul i picck up any at all 😥😥?
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    (Original post by varshanct95)
    how did people calculate r and s for 6 b) ?
    I wrote something like P(x)=k.A where A is the area of the region since we were told they are proportional. Then using the first to values in the table I found k and using that value of k I found each of the associated probabliities (by calculating each area) and hence found the expected values for each region..
 
 
 
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