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HomeWork is way too hard this week...another q Watch

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    (Original post by Fyer1234)
    Thanks

    but I do t have th z-score because I don't know what value or how to find the value I need to minus the mean with...?
    Oh, okay. So this question is doing it the other way round. You look in the table to see which z score corresponds to the top 10%. Then you know z, the mean and the standard deviation so you can use z=\frac{x-\mu}{\sigma} to find the score.
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    (Original post by brittanna)
    Oh, okay. So this question is doing it the other way round. You look in the table to see which z score corresponds to the top 10%. Then you know z, the mean and the standard deviation so you can use z=\frac{x-\mu}{\sigma} to find the score.
    Thanks

    lol I am so lost, been at this for 7 hours and f..I..g hate it.

    im looking at the normal distribution table and I can't tell what I'm looking for. I still don't see how the zscore helps though...

    Surely the cut-off score is 577 and the percentage of applicants who have test score within two sd of the mean is 95%

    i don't see why these two answers are wrong...
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    (Original post by Fyer1234)
    Thanks

    lol I am so lost, been at this for 7 hours and f..I..g hate it.

    im looking at the normal distribution table and I can't tell what I'm looking for. I still don't see how the zscore helps though...

    Surely the cut-off score is 577 and the percentage of applicants who have test score within two sd of the mean is 95%

    i don't see why these two answers are wrong...
    On page 19 of this document: https://www.edexcel.com/migrationdoc...cal-Tables.pdf
    .

    You can see that the z score corresponding to being in the top 10% is 1.2816. You can now put this into the standardisation formula.
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    (Original post by brittanna)
    On page 19 of this document: https://www.edexcel.com/migrationdoc...cal-Tables.pdf
    .

    You can see that the z score corresponding to being in the top 10% is 1.2816. You can now put this into the standardisation formula.
    Thanks for your help mate

    so, 1.2816 - 500 /60 = -8.316

    gosh that looks so wrong. If it is right, I still can't see how that fits into the question....?
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    (Original post by Fyer1234)
    Thanks for your help mate

    so, 1.2816 - 500 /60 = -8.316

    gosh that looks so wrong. If it is right, I still can't see how that fits into the question....?
    Remember 1.2816 is the z score, so 1.2816 = \frac{x - 500}{60}.

    Where x is the score needed to be in the top 10%.
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    (Original post by brittanna)
    Remember 1.2816 is the z score, so 1.2816 = \frac{x - 500}{60}.

    Where x is the score needed to be in the top 10%.
    thanks again

    so this is what I've got -rounded up if that's correct

    577-500/60 = z score...?

    so if 77 is correct, 577 is the cut-off score which means anything above 577 is in the top 10%

    I hope I'm getting closer lol
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    (Original post by Fyer1234)
    thanks again

    so this is what I've got -rounded up if that's correct

    577-500/60 = z score...?

    so if 77 is correct, 577 is the cut-off score which means anything above 577 is in the top 10%

    I hope I'm getting closer lol
    I think that's correct, yeah .
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    (Original post by brittanna)
    I think that's correct, yeah .

    Ok awesome! Hopefully someone can verify this

    thanks for your patience today, really really appreciated
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    Yes basically you are rearranging the formula to get x.
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    Ah ha ok thanks

    just one last thing on this bloomin question, is 95% correct for the 2nd part of it? I'm guessing it's not quite as simple as that lol

    thanks everyone for your patience
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    (Original post by Fyer1234)
    Ah ha ok thanks

    just one last thing on this bloomin question, is 95% correct for the 2nd part of it? I'm guessing it's not quite as simple as that lol

    thanks everyone for your patience
    Did you end up finding the answer eventually?
    what was it ?
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    (Original post by Fyer1234)
    Ah ha ok thanks

    just one last thing on this bloomin question, is 95% correct for the 2nd part of it? I'm guessing it's not quite as simple as that lol

    thanks everyone for your patience
    I think it is that simple.
    For a normal distribution, 95% of all data lies within 2 standard deviations away from the mean.
 
 
 
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