One of the factors of the electronegativity of an atom is the number of protons in the nucleus. The more protons in the nucleus, the greater the electronegativity, as the attraction to the electrons of another atoms is increased. After the periodic table the nitrogen has seven protons, but fluorine has nine. So fluorine has a greater attraction to the electrons of an atom and that is equivalent to the greater electronegativity.
(edited 9 years ago)
Original post by Kallisto
One of the factors of the electronegativity of an atom is the number of protons in the nucleus. The more protons in the nucleus, the greater the electronegativity, as the attraction to the electrons of another atoms is increased. After the periodic table the nitrogen has seven protons, but fluorine has nine. So fluorine has a greater attraction to the electrons of an atom and that is equivalent to the greater electronegativity.
Ah, that makes sense, thanks
Original post by Clarinet
Ah, that makes sense, thanks
You are welcome. Perhaps I should mention that electronegativity depends on the distance of the electrons (= distance of the shells) to the nucleus too. The greater the distance, the weaker the electronegativity. That is the reason why atoms with higher atomic numbers have a weaker electronegativity.
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