The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Intermediate Maths Challenge - UKMT - 5th February 2015

Scroll to see replies

Original post by patelvinai
What was 22?? i got 3/8?!

one third
Original post by SpeedieABC
21:2/9
23:112
25:5/8
(do you need explanations?)


I managed to get them all wrong, so explanations would be great, thanks! :colondollar:
Original post by SpeedieABC
I managed to do all the questions
they were really easy :smile:
these are my answers
im pretty sure they are almost all correct
Last year, i got 122 and top 50 in Cayly
and i want to get top 50 in Hamilton so i can go to Oxford summer school
these are
my answers:
1. 0.826
2. 130
3. 3/10
4. 54
5. 2 to the power of5
6. 2:3
7. 24
8. 2
9. 720
10. 4
11. 18
12. 2
13. 21
14. 44
15. 48
16. 2
17. 90
18. 3
19. 35
20. 270
21. 2/9
22. 1/3
23. 112
24. 13
25. 5/8

also, 12 (the ant question) was 6
i got 4:frown: then realised literally in last second
Original post by SpeedieABC
one third


Damn... you sure? how is it done??
Original post by Yuuchin1
also, 12 (the ant question) was 6
i got 4:frown: then realised literally in last second

how is that?
did it today, everyone always asks how it wet but the fact is i wouldn't put the answer if i didn't think it would be correct...duh
Original post by patelvinai
Damn... you sure? how is it done??

you work out the length of the sides of the small squares in comparison to the large square using the fact that the small squares are lining up at 45 degrees =2^1/2 times the length
i got 1/3 too (yay)
Original post by SpeedieABC
how is that?

you can go up then left as well
It was 6 ( i will delete this message in 3 mins)

there was a route from the flat surface up to the verticle surface, crossing over to the other verticle surface (which allows you to cross into the same colour as the one before- thereby allowing you to get to black in even number of moves)
there were 4 routes (2 routes from each side) that led to blacks on the verticle surfaces and 2 routes that led to 2 blacks onthe original surface coming back (i didnt realise this until last second and by then it was too late)

wish i had the diagram to explain better-sorry for confusing wording
its my previous post
Original post by Yuuchin1
you work out the length of the sides of the small squares in comparison to the large square using the fact that the small squares are lining up at 45 degrees =2^1/2 times the length
i got 1/3 too (yay)


ahhhh--- omg i screwed that up... thanks anyway
My answers:
1. A
2. E
3. E
4. C
5. B
6. D
7. E
8. B
9. B
10. A (confirmed wrong, actually C)
11. D
12. A (confirmed wrong, actually B)
13. A
14. C
15. E (confirmed wrong, actually C)
16. D
17. C (confirmed wrong, actually D)
18. B (presumed wrong, probably A)
19. C
20. C
21. C (marked 2/9 first and changed my mind ;()
22. A
23. B
24. E
25. D

Tallying these up I get 99, unless question 18 was actually correct. This is exactly what I got last year (also best in year and best in school) and I sat the Hamilton paper and got a merit with an abysmal score. Hope you all did well and the answers will be on the UKMT website tomorrow probably.
speedy you probably saw the ones that went back to the original surface but not remained on the verticle surface, while i vice versa.
wish i could share info with you during the exam then we wouldve both got it right
lol speedys an year below me and still got exactly the same things wrong as me (:redface:)
I SWEAR 10 is A.......
what was 10
Original post by Hanako13
I managed to get them all wrong, so explanations would be great, thanks! :colondollar:


21. shaded - X
One strip - Y

X = (Y + Y - X)/8
= 0.25Y - 0.125X
1.125X=0.25Y
9X = 2Y
X = 2/9 x Y

23

First Letter--------------------

C 1st to 24th
I 25th to 48th
K 49th to 72th
M 73th to 96th
U 97th to 120th

Second Letter---------------

C 97th to 102th
I 103th to 108th
K 109th to 114th
M 115th to 120th

Third Letter--------------------


C 109th to 110th
I 111th to 112th
M 113th to 114th

Fourth Letter--------------------

C 111th
M 112th



25.

non shaded area

1/4 x 3/4 x 2 =
3/8

1- 3/8 = 5/8
was that the remainder question
then it was 4 = c
Original post by Yuuchin1
what was 10


the one where you had to multiply the powers and divide by 8 or something like that....i can't remember the whole question but you get the gist
Original post by Yuuchin1
It was 6 ( i will delete this message in 3 mins)

there was a route from the flat surface up to the verticle surface, crossing over to the other verticle surface (which allows you to cross into the same colour as the one before- thereby allowing you to get to black in even number of moves)
there were 4 routes (2 routes from each side) that led to blacks on the verticle surfaces and 2 routes that led to 2 blacks onthe original surface coming back (i didnt realise this until last second and by then it was too late)

wish i had the diagram to explain better-sorry for confusing wording

sorry if i sound stupid but the ant can only travel 4 times right?

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you