# rate of reactionWatch

#1
hi guys,
i was wondering why the order of [A] and [B] are 1 and 2 respectively?

thanks
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3 years ago
#2
Comparing 1&2, doubling B quadruples rate, 2nd order WRT B.
Comparing 2&3, doubling B (again) should make rate x4, BUT it is x8, i.e. something has made rate x2 bigger than expected! Since A has doubled, it must be 1st order WRT A.
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#3
(Original post by Pigster)
Comparing 1&2, doubling B quadruples rate, 2nd order WRT B.
Comparing 2&3, doubling B (again) should make rate x4, BUT it is x8, i.e. something has made rate x2 bigger than expected! Since A has doubled, it must be 1st order WRT A.
Why A is first order? I still don't really understand
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3 years ago
#4
Comparing 2&3, [B] has doubled and since we know it is 2nd order WRT [B] rate should be 4x what is was in expt. 2, i.e. 12.06 (12.1 3s.f.). BUT rate is 24.1 in expt. 3, i.e. 2x higher than it should be! What is making expt. 3 go 2x faster than expected? Perhaps it has something to do with the fact that [A] is 2x bigger? Since [A] = 2x and rate is also 2x, it must be 1st order WRT [A].
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3 years ago
#5
(Original post by 041087)
Why A is first order? I still don't really understand
Do you understand what the order of a reaction means?
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