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    Ok i got an A at A level maths but upon starting Physics undergrad they've confused the hell out of me. WHat would you answer to this....

    Find the solution to dx/dt = 2

    Such that x = 5 at t = 1

    So im assuming im looking for a value in which case i need to work out the constant after I integrate.... Ive forgotten how to do this, do i use 5 and 1 or do i use x0 = x, t0 = t

    Someone answer it just so i get whats going on please! x x x

    dx/dt = 2
    Integrate both sides wrt t
    INT dx/dt dt = 2t + c
    INT dx = 2t + c (using the chain rule)
    x = 2t + c (note you only need one constant)

    Now substitute x=5 and t=1 to find c.
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