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    As a car passes the point A on s straight road, its speed is 10 m/s. The car moves with constant acceleration a m/s² along the road for T seconds until it reaches the point B, where its speed is V m/s. The car travels at this speed for a further 10 seconds, when it reaches point C. From C it travels for a further T seconds with constant acceleration 3a m/s² until it reaches a speed of 20 m/s at the point D. Show that V= 12.5

    Given that the distance between A and D is 675 m, Find the values of a and T

    For the first bit is it allowed to do a+3a = 4a and the change in speed is 10m/s, therefore 10/4 = 2.5 and 10 + 2.5 = 12.5?

    Also I have no idea what to do to find a and T

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    (Original post by bl64)
    As a car passes the point A on s straight road, its speed is 10 m/s. The car moves with constant acceleration a m/s² along the road for T seconds until it reaches the point B, where its speed is V m/s. The car travels at this speed for a further 10 seconds, when it reaches point C. From C it travels for a further T seconds with constant acceleration 3a m/s² until it reaches a speed of 20 m/s at the point D. Show that V= 12.5

    Given that the distance between A and D is 675 m, Find the values of a and T

    For the first bit is it allowed to do a+3a = 4a and the change in speed is 10m/s, therefore 10/4 = 2.5 and 10 + 2.5 = 12.5?

    Also I have no idea what to do to find a and T

    Form two equations using the formula acceleration=change in velocity/time taken. One for when the car is travelling from A to B and the second for when the car is travelling from C to D.

    Then to find a and T you will need to use the formula velocity=distance/time.
 
 
 
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