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    Hey guys,

    Probably a simple question but I seem to be having some difficulty in getting an answer so some help would be fantastic. Here goes...

    Two sheets of steel are riveted together with 5 rivets all in a row. Each rivet is 8mm in diameter. Calculate the safety factor if the ultimate shear stress is 60MPa and the maximum force required to break the joint is 10.52KN.

    Any help/advice would be great. Thanks
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    Stress = Force / Area
    You have area from the diameter and are given the force.
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    So because there are 5 rivets I just need to multiply the area by 5?

    Thanks for the speedy reply
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    (Original post by Pokeyguy20)
    So because there are 5 rivets I just need to multiply the area by 5?

    Thanks for the speedy reply
    Yes. You should hopefully find that 5 rivets is enough to hold the joint. Fewer rivets reduces the area and increases the stress.
 
 
 
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