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    1 / (1-x^2)

    Firstly I expressed the above as a partial fraction.

    0.5/(1-x) + 0.5/(1+x)

    Integrate the above to get

    0.5ln(1-x) + 0.5ln(1+x)

    where did I go wrong?
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    (Original post by khanpatel321)
    1 / (1-x^2)

    Firstly I expressed the above as a partial fraction.

    0.5/(1-x) + 0.5/(1+x)

    Integrate the above to get

    0.5ln(1-x) + 0.5ln(1+x)

    where did I go wrong?
    missed a minus in the first lump
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    (Original post by TeeEm)
    missed a minus in the first lump
    A=0.5 B=0.5?
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    (Original post by khanpatel321)
    A=0.5 B=0.5?
    no

    1/(1-x) integrates to -ln|1-x|
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    (Original post by TeeEm)
    no

    1/(1-x) integrates to -ln|1-x|
    So is the answer

    0.5ln(1+x) - 0.5ln(1-x) ?
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    (Original post by khanpatel321)
    So is the answer

    0.5ln(1+x) - 0.5ln(1-x) ?
    clearly
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    (Original post by TeeEm)
    clearly
    Thank you
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    (Original post by khanpatel321)
    Thank you
    no worries
 
 
 
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