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# Help - Q23 June 2011 - iGCSE watch

1. Hi,

I can't work this out at all - can somebody help me please?

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2. (Original post by ShivP_98)
Hi,

I can't work this out at all - can somebody help me please?

Express each of the numbers under the root in prime factors first

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3. (Original post by C0balt)
Express each of the numbers under the root in prime factors first

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Okay so

sqrt(3 * 16) + sqrt(3 * 36)

Like that?

4. squareroot = |

|(48) + |(108)

= |(3*16) + |(3*36)

= 4|(3) + 6|(3)

= 10|(3)
5. It needs to be in the form k sqrt6 though not 3
6. Also if anyone has any time;

This one is hard for me too
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7. Well, you know that is equal to .

You want each one in terms of , so what do you do?

Edit: Sorry, this was the more direct root route but I missed that other people were helping with a different method.
8. Try and make either a or b 6?
9. (Original post by ShivP_98)
It needs to be in the form k sqrt6 though not 3

Strange question but you have 10root3

And 10 is 5 x root2 x root2
10. (Original post by ShivP_98)
Also if anyone has any time;

This one is hard for me too
I assume that you can square what you have

Then you need to adapt to make a^2 less than 10
11. (Original post by sophie_emma96)
x = a X 10^n

x^2 = (a X 10^n)^2

x^2 = (a X 10^n)(a X 10^n)

FOIL method:
x^2 = a^2 + a10^n + a10^n + 100^2n

x^2 = a^2 + 100^2n + 2(a X 10^n)
This is incorrect ... Can suggest that you either correct it or delete it
12. (Original post by TenOfThem)
This is incorrect ... Can suggest that you either correct it or delete it
I don't know how to correct it so I will delete it haha! Could you share the correct answer as I'm intrigued now! 😂
13. (Original post by sophie_emma96)
I don't know how to correct it so I will delete it haha! Could you share the correct answer as I'm intrigued now! 😂
You squared a+b instead of ab

(ab)^2 = a^2b^2
14. (Original post by TenOfThem)
You squared a+b instead of ab

(ab)^2 = a^2b^2
Oops stupid error there, clearly need to get to bed

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