This is again from the Edexcel A2 Student's Book. I thought I would use the conservation of momentum here, but I assumed that since the KE of the neutron falls to 1MeV, this KE is gained by the proton, so the proton's KE becomes 3MeV. That doesn't seem to work, I have no idea how to solve this. :|
There is a similar question to this as well which I am having trouble at:
Protons are accelerated to an energy of 10GeV and the beam is made to collide head-on with a beam of anti-protons, also with an energy of 10GeV. How much energy is available from each collision to produce new particles? Take the proton mass as 940 MeV/c^2.
Calculating mass of a neutron after collision watch
- Thread Starter
Last edited by You-know-who; 11-01-2015 at 08:51.
- 11-01-2015 08:31