We are given the molecule Me2NPF4 and we record an NMR analysis at room temperature to obtain the 1 : 4 : 6 : 4 : 1 quintet which is to be expected. We then take the sample and cool it to -100C before taking the NMR analysis again. We obtain this time a quintet but with the inner 2 peaks as doublet and the central peak as a triplet (as shown in the attachment). The question asks for an explanation of how this occurs. However, my attempts so far haven't gotten me very close to a solution. Help is much appreciated.
Over the Easter break