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# business question with maths watch

1. I have this difficult question that I am trying to understand. It is a math’s question given in my Business lesson, I have the answer, however I do not how the solution was derived.

Three friends had formed a business buying run-down houses, doing them up and selling them on for a profit. Their first house cost them £100 000.

If Anthony had invested a third of the amount Basinder had put in, and half of Cathy’s, he could have bought the house by himself.

If Basinder had invested half of Anthony’s money and a quarter of Cathy’s he could have bought the house himself.

If Cathy had invested a quarter of Anthony’s money and one-sixth of Basinder’s, she could have bought the house herself.

How much money did each have to invest?

Here is the answer: Anthony £40000, Basinder £60000, Cathy £80000.
I have tried algebra and simultaneous equation but cannot find how the answer was calculated. I am rubbish at maths, so will need step by step instuctions to understand it.

Thank you

Here is the answer: Anthony £40000, Basinder £60000, Cathy £80000.
I have tried algebra and simultaneous equation but cannot find how the answer was calculated.
2. (Original post by msa969)
I have this difficult question that I am trying to understand. It is a math’s question given in my Business lesson, I have the answer, however I do not how the solution was derived.

Three friends had formed a business buying run-down houses, doing them up and selling them on for a profit. Their first house cost them £100 000.

If Anthony had invested a third of the amount Basinder had put in, and half of Cathy’s, he could have bought the house by himself.

If Basinder had invested half of Anthony’s money and a quarter of Cathy’s he could have bought the house himself.

If Cathy had invested a quarter of Anthony’s money and one-sixth of Basinder’s, she could have bought the house herself.

How much money did each have to invest?
.
We do not like to give full solutions but I am willing to help your understanding

To start with ... Your equations will be easier to work with if you eliminate the fractions

a+b/3+c/2 = 100000 gives 6a+2b+3c = 600000

Can you see what I gave done with Anthony ... If so can you do the same with the other two

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