# parametric curves - points of self intersection

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#1
I have a curve
r(t)=((2+cos(1.5t))cos(t))i + ((2+cos(1.5t)sin(t))j where t belongs to [0,4*pi] and I have drawn it out.
The question asks to find the points of self intersection, but I am unsure how to do this.
0
6 years ago
#2
(Original post by ellemay96)
I have a curve
r(t)=((2+cos(1.5t))cos(t))i + ((2+cos(1.5t)sin(t))j where t belongs to [0,4*pi] and I have drawn it out.
The question asks to find the points of self intersection, but I am unsure how to do this.
same x same y

look for the period of cos(3/2t)cost for a start...

any good?
0
#3
(Original post by TeeEm)
same x same y

look for the period of cos(3/2t)cost for a start...

any good?
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
0
6 years ago
#4
(Original post by ellemay96)
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
this all standard stuff for laplace

what is exactly the problem?
0
6 years ago
#5
i
(Original post by TeeEm)
this all standard stuff for laplace

what is exactly the problem?

(Original post by ellemay96)
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
ignore my last comment as this was a reply to a different thread

the procedure is standard but very long to explain.

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