parametric curves - points of self intersection

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ellemay96
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I have a curve
r(t)=((2+cos(1.5t))cos(t))i + ((2+cos(1.5t)sin(t))j where t belongs to [0,4*pi] and I have drawn it out.
The question asks to find the points of self intersection, but I am unsure how to do this.
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TeeEm
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(Original post by ellemay96)
I have a curve
r(t)=((2+cos(1.5t))cos(t))i + ((2+cos(1.5t)sin(t))j where t belongs to [0,4*pi] and I have drawn it out.
The question asks to find the points of self intersection, but I am unsure how to do this.
same x same y

look for the period of cos(3/2t)cost for a start...

any good?
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ellemay96
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(Original post by TeeEm)
same x same y

look for the period of cos(3/2t)cost for a start...

any good?
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
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TeeEm
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(Original post by ellemay96)
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
this all standard stuff for laplace

what is exactly the problem?
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TeeEm
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(Original post by TeeEm)
this all standard stuff for laplace

what is exactly the problem?

(Original post by ellemay96)
okay, so i've found that the period of cos(3/2t)cos(t) is 4pi. I still don't understand what to do next
ignore my last comment as this was a reply to a different thread


the procedure is standard but very long to explain.

look at this link or in similar links from google

https://www.google.co.uk/url?sa=t&rc...dyqvLvFxa_QF-w
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