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# C2 Polynomial Watch

1. Hiya, im stuck on a C2 polynomial question. It reads:

"Divide -3x4 + 8x2 + 13x - 10 by (x - 2)"

Thanks!
2. (Original post by JamesNeedHelp2)
Hiya, im stuck on a C2 polynomial question. It reads:

"Divide -3x4 + 8x2 + 13x - 10 by (x - 2)"

Thanks!
There are various methods

Long division
Equating coefficients

What have you tried?
3. (Original post by TenOfThem)
There are various methods

Long division
Equating coefficients

What have you tried?
Long division, but i cant get past the first step. thank you
4. (Original post by JamesNeedHelp2)
Long division, but i cant get past the first step. thank you
Did you remember to put the 0x^3 in
5. (Original post by TenOfThem)
Did you remember to put the 0x^3 in
no i did not. i will work it out and put my working on here. Maybe you can help me then? thanks.
6. (Original post by TenOfThem)
Did you remember to put the 0x^3 in
"Divide -3x4 + 8x2 + 13x - 10 by (x - 2)"

Where do i put the 0x3 in? is it supposed to look like this..."-3x4 + 0x3 + 8x2 + 13x - 10 by (x - 2)"

-3x3 - 5x2 - 2x - 9

(x- 2) x (-3x3) = -3x4 + 6x3

(-3x4 + 0x3) - (-3x4 + 6x3) = (-3x4 + 0x3) + (3x4 - 6x3) = -5x3 + 8x2

(x- 2) x ( -5x2) = -5x3 + 10x2

(-5x3 + 8x2) + (5x3 - 10x2) = -2x2 + 13x

(x- 2) x (-2x) = -2x2 + 4x

(-2x2 + 4x) - (-2x2 + 13x) = -9x - 10

Answer; -3x3 - 5x2 - 2x - 9
7. Put your terms in descending powers of x, so swap the first two
8. (Original post by offhegoes)
Put your terms in descending powers of x, so swap the first two
ahaaa that makes sense. thank you
9. (Original post by offhegoes)
Put your terms in descending powers of x, so swap the first two
"-3x4 + 0x3 + 8x2 + 13x - 10 by (x - 2)"

-3x3 - 5x2 - 2x - 9

(x- 2) x (-3x3) = -3x4 + 6x3

(-3x4 + 0x3) - (-3x4 + 6x3) = (-3x4 + 0x3) + (3x4 - 6x3) = -5x3 + 8x2

(x- 2) x ( -5x2) = -5x3 + 10x2

(-5x3 + 8x2) + (5x3 - 10x2) = -2x2 + 13x

(x- 2) x (-2x) = -2x2 + 4x

(-2x2 + 4x) - (-2x2 + 13x) = -9x - 10

Answer; -3x3 - 5x2 - 2x - 9
10. (Original post by JamesNeedHelp2)
"Divide -3x4 + 8x2 + 13x - 10 by (x - 2)"

Where do i put the 0x3 in? is it supposed to look like this..."-3x4 + 0x3 + 8x2 + 13x - 10 by (x - 2)"

-3x3 - 5x2 - 2x - 9

(x- 2) x (-3x3) = -3x4 + 6x3

(-3x4 + 0x3) - (-3x4 + 6x3) = (-3x4 + 0x3) + (3x4 - 6x3) = -5x3 + 8x2

(x- 2) x ( -5x2) = -5x3 + 10x2

(-5x3 + 8x2) + (5x3 - 10x2) = -2x2 + 13x

(x- 2) x (-2x) = -2x2 + 4x

(-2x2 + 4x) - (-2x2 + 13x) = -9x - 10

Answer; -3x3 - 5x2 - 2x - 9
Let me see if I can find your error

0- -6 is not -5 in your x^3
11. (Original post by TenOfThem)
Let me see if I can find your error

0- -6 is not -5 in your x^3
surely,-6x3 + x3 = -5x3?
12. (Original post by JamesNeedHelp2)
surely,-6x3 + x3 = -5x3?
Well, yes, -6+1=-5

But you had 0 and needed to subtract -6 and 0--6 = 6
13. (Original post by TenOfThem)
Well, yes, -6+1=-5

But you had 0 and needed to subtract -6 and 0--6 = 6
aaaah i see, im so retarded. Appreciated.

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