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# Area of sector of circle?? watch

1. Need
2. (Original post by iamspiderman)

(a) Area of segment OPQ-area of segment OXY
3. (Original post by iamspiderman)

Area of a sector is angle/360 x the area of the circle
4. (Original post by TenOfThem)
Area of a sector is angle/360 x the area of the circle

Ok so would it be:

Area of full circle
3.14 x 20^2 = 1256

Area of sector = 65/360 x 1256
= 226.7

Is this right??
5. (Original post by iamspiderman)
Ok so would it be:

Area of full circle
3.14 x 20^2 = 1256

Area of sector = 65/360 x 1256
= 226.7

Is this right??
For OPQ yes
6. (Original post by TenOfThem)
For OPQ yes

Ok but how would I find the area for XPQY?
7. (Original post by iamspiderman)

Ok but how would I find the area for XPQY?
You have the big sector so you need to find the small sector and take it away
8. (Original post by TenOfThem)
You have the big sector so you need to find the small sector and take it away
Ok,for XPQY I did:

Area= 3.14 x 10^2 = 314.16( I halved the radius)

Area of sector= 65/360 x 314.16 = 56.72

So OPQ - XPQY
226.7 - 56.72= 169.98

Is this right ?
9. (Original post by iamspiderman)
Ok,for XPQY I did:

Area= 3.14 x 10^2 = 314.16( I halved the radius)

Area of sector= 65/360 x 314.16 = 56.72

So OPQ - XPQY
226.7 - 56.72= 169.98

Is this right ?
Yes

Though you meant OPQ-OXY

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