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    (Original post by iamspiderman)


    Need help answering this question.....
    (a) Area of segment OPQ-area of segment OXY
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    (Original post by iamspiderman)


    Need help answering this question.....
    Area of a sector is angle/360 x the area of the circle
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    (Original post by TenOfThem)
    Area of a sector is angle/360 x the area of the circle

    Ok so would it be:

    Area of full circle
    3.14 x 20^2 = 1256

    Area of sector = 65/360 x 1256
    = 226.7

    Is this right??
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    (Original post by iamspiderman)
    Ok so would it be:

    Area of full circle
    3.14 x 20^2 = 1256

    Area of sector = 65/360 x 1256
    = 226.7

    Is this right??
    For OPQ yes
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    (Original post by TenOfThem)
    For OPQ yes
    Thanks for replying

    Ok but how would I find the area for XPQY?
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    (Original post by iamspiderman)
    Thanks for replying

    Ok but how would I find the area for XPQY?
    You have the big sector so you need to find the small sector and take it away
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    (Original post by TenOfThem)
    You have the big sector so you need to find the small sector and take it away
    Ok,for XPQY I did:

    Area= 3.14 x 10^2 = 314.16( I halved the radius)

    Area of sector= 65/360 x 314.16 = 56.72

    So OPQ - XPQY
    226.7 - 56.72= 169.98

    Is this right ?
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    (Original post by iamspiderman)
    Ok,for XPQY I did:

    Area= 3.14 x 10^2 = 314.16( I halved the radius)

    Area of sector= 65/360 x 314.16 = 56.72

    So OPQ - XPQY
    226.7 - 56.72= 169.98

    Is this right ?
    Yes

    Though you meant OPQ-OXY
 
 
 
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