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# Volumetric calculation watch

1. Please can you help me with question 7...

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2. Which part?

What are your thoughts? What specifically do you find tricky?

I don't want to do your homework for you.
3. 1000 cm3 NaOH contains 0.2 mol
80 cm3 NaOH contains 0.2/1000X80= 0.016

I hav to write the neutralisation reaction for NaOH with H2SO4 or HCl???
Then i can continue...

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4. Part b

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5. Both H2SO4 and HCl are acids, so both will neutralise the NaOH.
6. I knw these r acids and that it will neutralise the NaOH
The number of moles for NaOH.... With what should i do the mole ratio???

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7. Use H+ + OH- -> H2O.

For each mol of SOCl2, how many mol of H2SO4 and HCl form? and hence how many mol of H+?
8. SO2Cl2 +2H2O ---> H2SO4 + 2HCl
According to this... 3 mol of H+???

Mole ratio H+ : H2O
3. : 2
0.016 : 4/375

Mole ratio H2O : SO2Cl2
2. : 1
4/375. : 2/375
Mr(SO2Cl2)= 135
Mass= 135 X 2/375= 0.72g

Is it good???

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9. Please just do number 7 for me
Bcuz nmber 8 and 9,, as im reading the question will require the logic used in num 7
Plzzz😥😥😥

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10. 1 mol of SOCl2 does indeed produce 2 mol of HCl and 1 mol of H2SO4, but that doesn't form 4 mol of H+.

Also, I'll bet 9 will be different.
11. So how many mol of H+ does that produce???

If u help me with num 7, then i can do num 8 by myself!!!

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12. H2so4 -> 2h+ + so42-
13. H2SO4 and HCl dissociates respectively...

Then what do i use to find the number of moles of SO2Cl2???

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14. 1 mol of SOCl2 produces 4 mol of H+ which react with 1 mol each of OH-

Work out n(NaOH), which gives you n(H+), which gives you n(SOCl2), which allows you to calculate m(SOCl2)
15. 1000 cm3 NaOH contains 0.2 mol
80 cm3 NaOH contains 0.2/1000X80= 0.016 mol

Mole ratio NaOH: H+
1 : 4
0.016 : 0.064

Mole ratio H+: SO2Cl2
4 : 1
0.064 : 0.016

Mr(SO2Cl2)= 32+32+71= 135
Mass= 135 X 0.016= 2.16g

Is it good????

Also if u hav worked it out, could u plzz tell me the final correct answer...

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16. 1. n(NaOH) = c x v = 0.200 x 80.0/1000 = 0.160 mol
2. n(H+) = n(NaOH) = 0.160 mol
3. n(SOCl2) = n(H+) x 4 = 0.640 mol
4. m(SOCl2) = n(SOCl2) x Mr = 0.640 x (32.1+32.0+71.0) = 8.6464 g = 8.65 g

Step 2. is 1:1 since H+ + OH- -> H2O i.e. 1:1
17. Final answer must be 0.54g...

Its in the book!!!

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18. But forget abt it

Ill tell my teacher... Nxt week

Thx u for helping me😊😊😊

If theres other problem i will contact you

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19. Whoops, I did a x4 rather than div 4. There is 4x as much H+ as SOCl2, rather than the other way around. 0.5404 g is the correct answer.

I've had a verrrry long day.
20. Thank you once again...
You know this is my first year... Actually i'm still waiting for my SC results!!!

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