Calculating pH

(edited 9 years ago)

If you put the [OH^-] and Kw values into the equation, you can use the resulting [H^+] to calculate the pH (using pH = -log[H^+].

[OH^-] is equal to the concentration of the NaOH, btw.

Original post by crozibear96

If you put the [OH^-] and Kw values into the equation, you can use the resulting [H^+] to calculate the pH (using pH = -log[H^+].

So this would be correct?

10^-14 = [H^+] [0.1]

[H^+] = 10^-14 / 0.1

pH=-log(10^-14/0.1)

pH= 13

Posted from TSR Mobile

Original post by goodwinning

So this would be correct?

10^-14 = [H^+] [0.1]

[H^+] = 10^-14 / 0.1

pH=-log(10^-14/0.1)

pH= 13

Posted from TSR Mobile

The working out looks correct, so it should be right (I don't have a calculator with me to check).

Ok, thanks for your help 😄

Posted from TSR Mobile

No probies. :biggrin:

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