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# Calculating pH watch

1. ..
2. If you put the [OH^-] and Kw values into the equation, you can use the resulting [H^+] to calculate the pH (using pH = -log[H^+].
3. [OH^-] is equal to the concentration of the NaOH, btw.
4. (Original post by crozibear96)
If you put the [OH^-] and Kw values into the equation, you can use the resulting [H^+] to calculate the pH (using pH = -log[H^+].
So this would be correct?

10^-14 = [H^+] [0.1]

[H^+] = 10^-14 / 0.1

pH=-log(10^-14/0.1)

pH= 13

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5. (Original post by goodwinning)
So this would be correct?

10^-14 = [H^+] [0.1]

[H^+] = 10^-14 / 0.1

pH=-log(10^-14/0.1)

pH= 13

Posted from TSR Mobile
The working out looks correct, so it should be right (I don't have a calculator with me to check).
6. Ok, thanks for your help 😄

Posted from TSR Mobile
7. No probies.

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