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    I have attached the photo. I couldn't get to an answer I used quotient rule with product rule as well for a final answer I got 6√3.4a/4 + √3
    This is the question I need differentiating.
    If you could talk me through step I would be grateful.
    http://postimg.org/image/d02mmaj2l/
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    (Original post by joeheat)
    I have attached the photo. I couldn't get to an answer I used quotient rule with product rule as well for a final answer I got 6√3.4a/4 + √3
    This is the question I need differentiating.
    If you could talk me through step I would be grateful.
    http://postimg.org/image/d02mmaj2l/
    This is simple term-by-term differentiation. Why on earth would you need to use the product and/or quotient rule? Each term is in the form:

    na^b where n and b are constants. Which can be directly differentiated.
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    (Original post by SamKeene)
    This is simple term-by-term differentiation. Why on earth would you need to use the product and/or quotient rule? Each term is in the form:

    na^b where n and b are constants. Which can be directly differentiated.
    could you talk me through it please much appreciated
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    (Original post by joeheat)
    could you talk me through it please much appreciated
    Well we have:

    \frac{3\sqrt{3}}{2}a^2+\frac{2}{  \sqrt{3}}a^{-1}

    Then we do the 'ol Multiply by the power and then take one off the power for each term.


    \frac{6\sqrt{3}}{2}a-\frac{2}{\sqrt{3}}a^{-2}

    And then it's just simplifying the fractions and rationalizing them, which I'll leave for you.
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    (Original post by SamKeene)
    Well we have:

    \frac{3\sqrt{3}}{2}a^2+\frac{2}{  \sqrt{3}}a^{-1}

    Then we do the 'ol Multiply by the power and then take one off the power for each term.


    \frac{6\sqrt{3}}{2}a-\frac{2}{\sqrt{3}}a^{-2}

    And then it's just simplifying the fractions and rationalizing them, which I'll leave for you.
    Thank you very much for the help much appreciated.
 
 
 
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