Blue7195
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#1
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How would you go about proving that,

s =  \frac{n-1}{n+1} with  n=1, 2, 3, ..., s \in \mathbb{R}

Is bounded? I tried with m >= s >= M but don't get very far...
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DFranklin
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Is s > 0? Is s < 1?
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Blue7195
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#3
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(Original post by DFranklin)
Is s > 0? Is s < 1?
The question doesn't say, just that s is in R and n = 1, 2, 3, ..
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DFranklin
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(Original post by Blue7195)
The question doesn't say, just that s is in R and n = 1, 2, 3, ..
I know. I'm asking you to answer what I asked...

You may need to do a tiny bit of algebra...
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Blue7195
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(Original post by DFranklin)
I know. I'm asking you to answer what I asked...

You may need to do a tiny bit of algebra...
Oh sorry, I worked out the infimum and supremum to be 0 and 1 so yeah. Is that all you need to show?
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DFranklin
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(Original post by Blue7195)
..
A sequence a_n is bounded if we can find constants m, M s.t. m <= a_n <= M for all n.

Without wanting to snark, the first thing you need to do when answering a question is making sure you understand the terms being used. Finding the sup, inf is not necessary here.
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Blue7195
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(Original post by DFranklin)
A sequence a_n is bounded if we can find constants m, M s.t. m <= a_n <= M for all n.

Without wanting to snark, the first thing you need to do when answering a question is making sure you understand the terms being used. Finding the sup, inf is not necessary here.
Ah okay thanks a lot!
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