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# mechanics -- torque problem Watch

1. How do we solve the problem? The solution provided in the picture above makes it look easy but I don't understand the approach they have taken. How can you just 'break' the rod with only the 250 Nm torque and point C for example, to find the internal torque at C?

Help would be appreciated.
2. (Original post by leosco1995)

How do we solve the problem? The solution provided in the picture above makes it look easy but I don't understand the approach they have taken. How can you just 'break' the rod with only the 250 Nm torque and point C for example, to find the internal torque at C?

Help would be appreciated.
Isn't what they've done at c simply balancing torques? I.e. there's a 250Nm one, and some effective torque at c required to balance it? I'm not too sure though...
3. (Original post by leosco1995)

How do we solve the problem? The solution provided in the picture above makes it look easy but I don't understand the approach they have taken. How can you just 'break' the rod with only the 250 Nm torque and point C for example, to find the internal torque at C?

Help would be appreciated.
To calculate the resultant internal torque at a point, we imagine a plane passing through the shaft, perpendicular to it at that point. Then it's a simply case of balancing the torques. In the case of point c, you'd have an unbalanced 250Nm torque, hence the internal torque at c would be 250Nm. In the case of d, there is nothing to balance.
4. Alright, I think I understand. Thanks for the help.

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