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# Help with a logs question watch

1. Hi can anyone help me understand this question please

My teacher said we have to take logs of both sides which I think I did but I still don't get it.
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2. You've done it right so far - just rearrange your equation now so that all the logs are on one side, and all the x terms on the other. You can then solve it to find x
3. xlog 2 = 1-xlog3

xlog2 + xlog3 = 1

x(log2 + log3) = 1

x = 1/(log2 + log3)

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4. (Original post by Positron.)
xlog 2 = 1-xlog3

xlog2 + xlog3 = 1

x(log2 + log3) = 1

x = 1/(log2 + log3)

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Not quite it's (1-x)log3
5. (Original post by Actaeon)
You've done it right so far - just rearrange your equation now so that all the logs are on one side, and all the x terms on the other. You can then solve it to find x
(Original post by Positron.)
xlog 2 = 1-xlog3

xlog2 + xlog3 = 1

x(log2 + log3) = 1

x = 1/(log2 + log3)

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Thanks guys, I didn't know you could separate the xlog3 from 1-xlog3

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6. (Original post by Light_bulb)
Not quite it's (1-x)log3
Oops lol. How did you know?

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7. (Original post by matalyst)
Thanks guys, I didn't know you could separate the xlog3 from 1-xlog3

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You can't it's (1-x)log3 then expand and use log rules
8. (Original post by matalyst)
Thanks guys, I didn't know you could separate the xlog3 from 1-xlog3

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Sorry my friend. I think i did it wrong. The 1-xlog3 is one term

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9. (Original post by Positron.)
Oops lol. How did you know?

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Using log rules
10. Ah okk I'm pretty sure I get it now thanks to the help.
I got x=0.613 which works when subbed in

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Updated: January 24, 2015
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