You are Here: Home >< Maths

# FP3 Hyperbolic Functions (edexcel) watch

1. Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
Attached Images

2. (Original post by WatermelonJuice1)
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
you should not lose marks

can you see how to switch between these 2 answers?
3. (Original post by TeeEm)
you should not lose marks

can you see how to switch between these 2 answers?
Nope, not really :/
4. (Original post by WatermelonJuice1)
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
That's fine. You might be interested in exploring surd denesting however. If you send me a private message I will send you a short article I wrote about this.
5. (Original post by WatermelonJuice1)
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
Lucky you doing FP3 <3
You're in year 13? Which module do you think has helped you the most in FP3?
6. (Original post by WatermelonJuice1)
Hi all,

I can't get my answer into the form they've got it in even though it has the same value. Solution attached.

Would I get marked down for this in an exam?
It's difficult to work through to their form from where you are, but if you use the fact, that kln(m) = ln(m^k), it's a bit easier to see. As for whether you'd get marked down, I think you would if they explicitly asked for a particular form.
7. (Original post by Placeboo123)
Lucky you doing FP3 <3
You're in year 13? Which module do you think has helped you the most in FP3?
I just started it last week so I can't really judge very accurately. So far I'd say FP2.
8. (Original post by WatermelonJuice1)
Nope, not really :/
1/2ln(3+2√2)

=ln[√(3+2√2)]

=ln[12 +2x1x√2+(√2)2]

=ln[√(1+√2)2]

=ln[1+√2]
9. (Original post by TeeEm)
1/2ln(3+2√2)

=ln[√(3+2√2)]

=ln[12 +2x1x√2+(√2)2]

=ln[√(1+√2)2]

=ln[1+√2]
You lost me on the 3rd line, but I'm reading into a surd denesting article Mr M sent me so hopefully it will make sense soon.

EDIT: Just read your response again and I get it. Thank you.
10. (Original post by WatermelonJuice1)
You lost me on the 3rd line, but I'm reading into a surd denesting article Mr M sent me so hopefully it will make sense soon.
I am using (a+b)2 = a2 +2ab+b2

I hope it makes sense one way or another.

good luck

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: January 25, 2015
Today on TSR

### Edexcel GCSE Maths Unofficial Markscheme

Find out how you've done here

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams