# Calculating currentWatch

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#1
I don't understand what to do with this and also is that a lower-case delta? If so, what does it mean?

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5 years ago
#2
(Original post by goodwinning)

I don't understand what to do with this and also is that a lower-case delta? If so, what does it mean?

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Resistance is measure in ohms and is always denoted by omega.

The symbol in the question looks like a very stylised (unusual) upper case omega, I have never seen it in quite that form before.
The symbol for resistance is always .

The question asks you to use logarithms which implies an exponential term is stated somewhere else in the problem. Is this part of an exponential decay or rise or perhaps in the context of a time constant?

Current I is simply 25/8 = 3.125 amperes.

Post the whole question so that the context can be understood and I can give a better answer.
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5 years ago
#3
(Original post by goodwinning)

I don't understand what to do with this and also is that a lower-case delta? If so, what does it mean?

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this is basic ohms law I is currant V is voltage band R is resistance youve had the equation V=IR transposed for you already you have V and you have R once you have worked out I the other equations to use are

V=IR
R=V/I

ps I have a degree in electronic engineering.
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#4
I know how to use Ohm's law but it's the other parts of the problem I don't understand like how to solve this using logarithms and that weird symbol (which has now been sort of explained).That's why I'm so confused what to do because it also says use logarithms and I don't even know how that's possible with the information given.

By the way, that is the whole question.

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5 years ago
#5
(Original post by goodwinning)
I know how to use Ohm's law but it's the other parts of the problem I don't understand like how to solve this using logarithms and that weird symbol (which has now been sort of explained).That's why I'm so confused what to do because it also says use logarithms and I don't even know how that's possible with the information given.

By the way, that is the whole question.

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Without the wider context, it cannot be answered with anything other than an assumption of ohms law.

Is this question from a text book? If so which?
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#6
It's part of an assignment that I have to do for my course: I'm doing a BTEC level 3 in applied science. It's really annoying me because if I don't get all the answers in this assignment correct I won't get a distinction in the maths unit which is really important for me to get into uni.

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5 years ago
#7
(Original post by goodwinning)
It's part of an assignment that I have to do for my course: I'm doing a BTEC level 3 in applied science. It's really annoying me because if I don't get all the answers in this assignment correct I won't get a distinction in the maths unit which is really important for me to get into uni.

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I found the symbol, it's from the Microsoft 'Windings' font set and is used in astrology as the symbol for the Leo starsign.

Looks highly likely they used it in error and it's meant to be omega.

What is the maths question you are struggling with? It may make more sense to post it in here if it's physics based.
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5 years ago
#8
(Original post by goodwinning)
It's part of an assignment that I have to do for my course: I'm doing a BTEC level 3 in applied science. It's really annoying me because if I don't get all the answers in this assignment correct I won't get a distinction in the maths unit which is really important for me to get into uni.

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If it's "part of" an assignment it may be helpful if you could provide the rest of the context for this as it makes no sense on its own.
Please post the text/diagrams/instructions of the assignment leading up to this question.
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#9
(Original post by Stonebridge)
If it's "part of" an assignment it may be helpful if you could provide the rest of the context for this as it makes no sense on its own.
Please post the text/diagrams/instructions of the assignment leading up to this question.
All the other questions in the assignment have nothing to do with this one and what I've posted is all I was given to work with for this problem, hence why I got very stuck despite all my attempts to try and research similar problems and had to resort to posting it on here for any suggestions.

There are no other text/diagrams/instructions. I'm not stupid enough to ask for help on a forum and not provide all the information I was given.

I have asked my brother, who is an electrical engineer, how to do this and he can't make sense of how to solve this with logarithms either and nor can my friends who are studying engineering.

Seems to me that this problem simply doesn't make sense and I'll just have to complain about it to my teacher.

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#10

That's the assignment I was given.

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#11
(Original post by goodwinning)

That's the assignment I was given and that was it. We weren't even provided with any resources on how to solve these either.

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5 years ago
#12
It looks to me that Task 7 is just an exercise in using logarithms.

For part 7.2 find the logs of the two numbers, subtract (log 25 - log 8) and then find the antilog of the result.
Check the answer by doing the calculation directly =25/8

It's not really much to do with Ohm's Law. Just division using logs.
0
5 years ago
#13
(Original post by goodwinning)

That's the assignment I was given.

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Stonebridge hits the nail on the head in his post #12.

I deleted my last answer out of embarrassment.

I hate you Stonebridge! LOL

Spoiler:
Show
I like you really.
0
5 years ago
#14
(Original post by uberteknik)
Stonebridge hits the nail on the head in his post #12.

I deleted my last answer out of embarrassment.

I hate you Stonebridge! LOL

Spoiler:
Show
I like you really.
Ha. Ha.
I've altered my answer slightly as I had the numbers in the fraction for I = V/R the wrong way round.

Spoiler:
Show

I like you too.
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#15
Yeah, thanks a lot Stonebridge! 😄

It actually occurred to me in the beginning that you just might need to apply the logarithm law to it but when I was told (by a teacher no less) that symbol was a lower-case delta it threw me off. Still can't believe they put an astrology sign there.

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