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# Area of a curve with a parabola watch

1. I am stuck on the 3rd question.

y=x^2-5x+4. I then factorised that to (x+5) and (x-1)

Therefore; x=-5 and x=1

I integrated to get this:

I thought that I would need to find the range of (0; -5) (1, 5) (1,0) and (1, -5)

Not 100% sure though.
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2. (Original post by apronedsamurai)
I am stuck on the 3rd question.

y=x^2-5x+4. I then factorised that to (x+5) and (x-1)

Therefore; x=-5 and x=1

I integrated to get this:

I thought that I would need to find the range of (0; -5) (1, 5) (1,0) and (1, -5)

Not 100% sure though.
Your factorisation is wrong:

3. (Original post by notnek)
Your factorisation is wrong:

Ok, (x-4)(x-1)

x=4; x=1
4. (Original post by apronedsamurai)
Ok, (x-4)(x-1)

x=4; x=1
Do you still need help?
5. Sadly, yes.

I thought that I would get the area where, 4 and 1 where the integers.

using the integrated forms, my final answer was (-) 13/6; (I have put brackets around the negative sign to denote the fact that I am aware that you disregard the negatives with the areas).

There are a total of three answers given: 1,4 and 6 to a 1/3

:s

Am now utterly lost :/
6. Where did they get three values from?
7. (Original post by apronedsamurai)
Sadly, yes.

I thought that I would get the area where, 4 and 1 where the integers.

using the integrated forms, my final answer was (-) 13/6; (I have put brackets around the negative sign to denote the fact that I am aware that you disregard the negatives with the areas).

There are a total of three answers given: 1,4 and 6 to a 1/3

:s

Am now utterly lost :/
I think I may know what you're doing wrong but your answer is not what I expected.

So can you post your working?

I'm not sure what you mean by "3 answers given". Do you mean for parts a), b) and c)? The correct answer for c) is .
8. The answer section of the book gives threes results/answers:

1, 4 and 6 1/3

Ok my working.

=-8/3

= - 1/2

=
9. (Original post by apronedsamurai)
The answer section of the book gives threes results/answers:

1, 4 and 6 1/3
1 and 4 are where the graph cuts the x-axis. That's the first part of the question.

The second part asks you to find the area and that answer is .
10. No, I am focusing solely and exclusively on c).

For c) the answers listed for that question are:

1, 4 and 6 1/3
11. (Original post by apronedsamurai)
No, I am focusing solely and exclusively on c).

For c) the answers listed for that question are:

1, 4 and 6 1/3
Read my last post.
12. Sorry that was a delayed response, in response to one of your previous posts.

Ok; so in essence then I had already identified 2 of the 3 answers.

So where am I going wrong, with regards to getting 6 1/3?
13. (Original post by apronedsamurai)
The answer section of the book gives threes results/answers:

1, 4 and 6 1/3

Ok my working.

=-8/3

= - 1/2

=
You're using instead of .

The latter is the correct version, which you gave in your initial post.

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