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Would you please help me with this histogram question watch

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    Thank you very much in advance.
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    (Original post by Syndy)
    ...
    \displaystyle \text{Frequency density} = \frac{\text{frequency}}{\text{cl  ass width}}

    Rearranging:

    \displaystyle \text{Frequency} = \text{frequency density}\times \text{class width}

    In other words, area in a histogram represents frequency. Does that help?

    This question looks familiar - IGCSE I think.
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    (Original post by Syndy)

    Thank you very much in advance.
    That block is 7.2 square cm

    It represents 18 people

    Hence ... ...
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    (Original post by notnek)
    \displaystyle \text{Frequency density} = \frac{\text{frequency}}{\text{cl  ass width}}

    Rearranging:

    \displaystyle \text{Frequency} = \text{frequency density}\times \text{class width}

    In other words, area in a histogram represents frequency. Does that help?

    This question looks familiar - IGCSE I think.
    Yes it is IGCSE question paper 4 . Thank you very much for your help.
 
 
 
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