Perms And ComsWatch
So if we did it like the abc example, how many words would we have?
But, for example, we have 3Os so there are 3! ways we can organise the Os, so we need to divide by something...
Do the same for the other letters with repetition.
For no two Os together, treat OO as one letter. So now you have:
So work out how many words there can be like this.
But this is working out how many have OO together, so you need to subtract this number from something to get the answer.
I hope this helps somehow. It's hard to explain it without just giving the calculations. :-/
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