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C4 Integration Maths Question: Where did I go wrong..? watch

1. I've attached my working out!

Attached Images

2. (Original post by creativebuzz)
I've attached my working out!

sin2x = 2sinxcosx

very first line
3. You've calculated the integral of cos(x)^2sin(x)^2 not 1/that.
4. (Original post by TeeEm)
sin2x = 2sinxcosx

very first line

Ah thank you!

Could you spot where I went wrong in this question:

Attached Images

5. (Original post by tiddlytom)
You've calculated the integral of cos(x)^2sin(x)^2 not 1/that.
Ah thank you!

Could you spot where I went wrong in this question?

Attached Images

6. (Original post by creativebuzz)
Ah thank you!

Could you spot where I went wrong in this question:

i do not see anything wrong
7. (Original post by TeeEm)
i do not see anything wrong
Oh okay, because when I tried plugging

1/tan(7 x pi/2) into my calculator I kept getting an error..

Am I plugging it into the calculator wrong or?
8. (Original post by creativebuzz)
Oh okay, because when I tried plugging

1/tan(7 x pi/2) into my calculator I kept getting an error..

Am I plugging it into the calculator wrong or?

I suspect your calculator is not good enough to handle it.
9. (Original post by TeeEm)
I suspect your calculator is not good enough to handle it.

..so what should I do? :/
10. (Original post by creativebuzz)
..so what should I do? :/
do you know what is the tan(pi/2)?
11. (Original post by creativebuzz)
Ah thank you!

Could you spot where I went wrong in this question?
When you evaluate the bottom limit, you get 2.275. I think it should be 1.23.

12. (Original post by tiddlytom)
When you evaluate the bottom limit, you get 2.275. I think it should be 1.23.

A

Ah got it! Thank you!

Do you know where I could go with this question?

Attached Images

13. (Original post by TeeEm)
do you know what is the tan(pi/2)?
Isn't there an asymptote there? Hence, the error
14. (Original post by creativebuzz)
Isn't there an asymptote there? Hence, the error
asymptote: yes
error: no
15. (Original post by TeeEm)
asymptote: yes
error: no
So how come I get an error every time I attempt it in my calculator?
16. (Original post by creativebuzz)
So how come I get an error every time I attempt it in my calculator?
17. (Original post by creativebuzz)
A

Ah got it! Thank you!

Do you know where I could go with this question?
The integral of -4/(2x+1) is done in the same way as the other term. (the top is a constant factor times the derivative of the bottom)
18. (Original post by creativebuzz)
A

Ah got it! Thank you!

Do you know where I could go with this question?

fixed
Attached Images

19. (Original post by tiddlytom)
The integral of -4/(2x+1) is done in the same way as the other term. (the top is a constant factor times the derivative of the bottom)

Ah okay! By the way, have you done FP1/Further Maths?
20. (Original post by creativebuzz)
Ah okay! By the way, have you done FP1/Further Maths?
Yeah, did further maths a few years ago - doesn't guarantee I remember it all!

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Updated: January 29, 2015
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