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FP2 transforming in the complex plane

ImageUploadedByStudent Room1422554165.846274.jpg

For c I've shown that arg(w+1+2i)=pi/4 however the answer says it's 3pi/4

For d I've shown that z+2=1/w by rearranging to find z and adding on +2 however i can't seem to get arg(w)=-PI/4


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Sorted part c.
For d i get arg(1)-arg(w)=pi/4



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Reply 2
Original post by Mutleybm1996
Sorted part c.
For d i get arg(1)-arg(w)=pi/4



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for c factorize the -i out

split the arg

arg(-i) = -pi/2

-pi/2 + arg(w+1+2i) = pi/4


edit too late
Original post by TeeEm
for c factorize the -i out

split the arg

arg(-i) = -pi/2

-pi/2 + arg(w+1+2i) = pi/4


edit too late


Argh, being so stupid! I've just realised how to do d too :smile: thanks though


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Reply 4
Original post by Mutleybm1996
Sorted part c.
For d i get arg(1)-arg(w)=pi/4



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for d

z+2 = 1/w
arg(z+2) = arg(1/w)
pi/4 = arg(1/w)
pi/4 = -arg(w)
argw = -pi/4
Original post by TeeEm
for d

z+2 = 1/w
arg(z+2) = arg(1/w)
pi/4 = arg(1/w)
pi/4 = -arg(w)
argw = -pi/4

Could you possibly have a look at 4c/d? My working is attached
ImageUploadedByStudent Room1422556055.040477.jpg
ImageUploadedByStudent Room1422556077.975995.jpg


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Reply 6
Original post by Mutleybm1996
Could you possibly have a look at 4c/d? My working is attached
ImageUploadedByStudent Room1422556055.040477.jpg
ImageUploadedByStudent Room1422556077.975995.jpg


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I can only see (c) and I disagree (I think)
Original post by TeeEm
I can only see (c) and I disagree (I think)


Could you possibly provide a hint?


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Reply 8
Original post by Mutleybm1996
Could you possibly provide a hint?


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second line from the bottom

in the LHS i think you lost the denominator
Original post by TeeEm
second line from the bottom

in the LHS i think you lost the denominator


So i now have 1=mod(iw-2w+2i)
Any advice on where to go from here?
Would i say 1=mod(i(w+2)-2w)?

Weird, the Book says the answer is mod(w-1/5 (-2+4i))=1/sqrt5

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(edited 9 years ago)
Reply 10
Original post by Mutleybm1996
So i now have 1=mod(iw-2w+2i)
Any advice on where to go from here?
Would i say 1=mod(i(w+2)-2w)?


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it is a nasty circle

either put w=u+iv and simplify

or


factorize the coefficient of w
then pull it out of the mod

etc

harder
Original post by TeeEm
it is a nasty circle

either put w=u+iv and simplify

or


factorize the coefficient of w
then pull it out of the mod

etc

harder


Well now I have absolutely no idea!
Sorry...I'm probably just being useless
ImageUploadedByStudent Room1422561892.854766.jpg


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(edited 9 years ago)
Reply 12
Original post by Mutleybm1996
Well now I have absolutely no idea!
Sorry...
ImageUploadedByStudent Room1422561892.854766.jpg


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it is correct so far

|A(u,v) + iB(u,v)| = 1

SRoot(A2+B2) = 1

square both sides etc
Original post by TeeEm
it is correct so far

|A(u,v) + iB(u,v)| = 1

SRoot(A2+B2) = 1

square both sides etc


ImageUploadedByStudent Room1422562869.123582.jpg

Is this any closer?


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Reply 14
Original post by Mutleybm1996
ImageUploadedByStudent Room1422562869.123582.jpg

Is this any closer?


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your method is correct but you have made silly computational errors.

If you supply an email address and I will post the solution (2 methods)
Reply 15
Original post by Mutleybm1996
ImageUploadedByStudent Room1422562869.123582.jpg

Is this any closer?


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look at the alternative method in purple
(this approach is a bit hard for students generally)
Original post by TeeEm
look at the alternative method in purple
(this approach is a bit hard for students generally)


I understand the principle, whether I'd be able to reproduce it is another matter!
Thanks, I may post again if I get stuck on 4d


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Reply 17
Original post by Mutleybm1996
I understand the principle, whether I'd be able to reproduce it is another matter!
Thanks, I may post again if I get stuck on 4d


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my pleasure
Original post by TeeEm
my pleasure


Hi, for d I managed to find and plot the two points easily enough, however don't quite understand what the 3pi/4 has to do with the problem?


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Reply 19
Original post by Mutleybm1996
Hi, for d I managed to find and plot the two points easily enough, however don't quite understand what the 3pi/4 has to do with the problem?


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I have not got a clue which question you are referring to ...

post the workings for this question

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