x Turn on thread page Beta
 You are Here: Home >< Maths

# WD Line Integrals watch

1. Calculate the work done by the force field along the curve of intersection of the sphere , the cylinder , and the halfspace . The path is traversed in a direction that appears clockwise when viewed from the high above the -plane.

How do I even find the path for starters... after that it is straight forward.

I know what the sphere would look like in the xyz plane but not the cylinder. How do you sketch the cylinder?
2. (Original post by cooldudeman)
Calculate the work done by the force field along the curve of intersection of the sphere , the cylinder , and the halfspace . The path is traversed in a direction that appears clockwise when viewed from the high above the -plane.

How do I even find the path for starters... after that it is straight forward.

I know what the sphere would look like in the xyz plane but not the cylinder. How do you sketch the cylinder?
simultaneous equations?
3. (Original post by TeeEm)
simultaneous equations?
Ok so subbing in the cylinder equation the way it is written to the sphere gives x+z^2=1 which would some kind of parabola. What variable do you rearrange this new equation to?
4. (Original post by cooldudeman)
Ok so subbing in the cylinder equation the way it is written to the sphere gives x+z^2=1 which would some kind of parabola. What variable do you rearrange this new equation to?
some parametric representation
when you need the parameter ends
start and finish for t
5. (Original post by TeeEm)
some parametric representation
when you need the parameter ends
start and finish for t
So so if we rearrange it to x=1-z^2, so let r(t)=1-t^2 but I have no idea how to find the limits...

Posted from TSR Mobile
6. (Original post by cooldudeman)
So so if we rearrange it to x=1-z^2, so let r(t)=1-t^2 but I have no idea how to find the limits...

Posted from TSR Mobile
I need to look at the question in detail (sometime tomorrow afternoon) as I am in the middle of my own work and also helping another individual.

7. (Original post by TeeEm)
I need to look at the question in detail (sometime tomorrow afternoon) as I am in the middle of my own work and also helping another individual.

Ok ill try PM him

Posted from TSR Mobile
8. (Original post by cooldudeman)
Ok ill try PM him

Posted from TSR Mobile
9. (Original post by TeeEm)
Turns put he's busy too. Damn oh well.

Posted from TSR Mobile
10. (Original post by cooldudeman)
Turns put he's busy too. Damn oh well.

Posted from TSR Mobile
I am looking at the question now
11. (Original post by cooldudeman)
Turns put he's busy too. Damn oh well.

Posted from TSR Mobile
12. (Original post by TeeEm)
I am looking at the question now

Posted from TSR Mobile
13. (Original post by cooldudeman)

Posted from TSR Mobile
very hard to picture

definitely I am too tired to complete this tonight
14. (Original post by cooldudeman)

Posted from TSR Mobile
very hard to picture

definitely I am too tired to complete this tonight

do you know what the answer is meant to be
15. (Original post by TeeEm)
very hard to picture

definitely I am too tired to complete this tonight

do you know what the answer is meant to be
I actually don't. Thanks please look at it when u can.

Posted from TSR Mobile
16. (Original post by cooldudeman)
I actually don't. Thanks please look at it when u can.

Posted from TSR Mobile
can you check if this field is conservative!!!
17. (Original post by cooldudeman)
I actually don't. Thanks please look at it when u can.

Posted from TSR Mobile
I got an answer of pi/4

if my initial modelling is correct (parameterization of the path) then it is all correct.
18. (Original post by TeeEm)
I got an answer of pi/4

if my initial modelling is correct (parameterization of the path) then it is all correct.
How did you find the path though?
19. (Original post by cooldudeman)
How did you find the path though?
I will attach my attempt and by no means solution ...

IMG_0001.pdf
20. (Original post by TeeEm)
I will attach my attempt and by no means solution ...

IMG_0001.pdf
thanks looking at it now! I'll have another solid go and see if I get the same. I'll let you know by tomorrow.

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: January 31, 2015
Today on TSR

### How much will your degree earn you?

Find out where yours ranks...

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams