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    The point A(-3,-7) lies on the circle centre (5,1). Find the equation of the tangent to the circle at A.
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    (Original post by Bevin)
    The point A(-3,-7) lies on the circle centre (5,1). Find the equation of the tangent to the circle at A.
    What have you tried/are your thoughts?
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    You need to find the other point that makes the line, then plug in the values of midpoint to get the second point. Then get a gradient. Remember that perpendicular lines are negative reciprocal and then form an equation.


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    if you didn't figure it out yet

    m1 (AC) = 8/8 = 1
    since we're finding the tangent it's the perpendicular gradient we need to find so m1m2=-1
    m2 = -1

    then use y-y1=m(x-x1) with m2 and at point A
    y+7=-1(x+3)
 
 
 
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