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# Help on a maths question Watch

1. Hi guys, it would be great if you guys could help me answer this question.
thanks.

2. (Original post by Chittesh14)
Hi guys, it would be great if you guys could help me answer this question.
thanks.

Attachment 360039
3. (Original post by TeeEm)

Sorry bro, don't know what the problem was, still works fine for me. But re-uploaded onto this post.
Attached Images

4. (Original post by Chittesh14)
Hi guys, it would be great if you guys could help me answer this question.
thanks.

That's not a question - that's just an expression!

Are you being asked to simplify what's written? There are several ways of going about this - one way is to start by writing what's inside the brackets as a power of some fraction. Can you do that?
5. (Original post by davros)
That's not a question - that's just an expression!

Are you being asked to simplify what's written? There are several ways of going about this - one way is to start by writing what's inside the brackets as a power of some fraction. Can you do that?
Yeah, sorry I kept doing it wrong lol. I was doing something else like doing 1/4 to the power of -2 and then writing a after it. But, my brother solved it for me and it is correct. I was meant to simplify it and I got the answer as 16a^4.
6. (Original post by Chittesh14)
Yeah, sorry I kept doing it wrong lol. I was doing something else like doing 1/4 to the power of -2 and then writing a after it. But, my brother solved it for me and it is correct. I was meant to simplify it and I got the answer as 16a^4.
Your brother was wrong if you're saying he got
7. (Original post by Phichi)
Your brother was wrong if you're saying he got
8. (Original post by Chittesh14)
No its not. Rewrite the middle part.

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9. (Original post by Chittesh14)
It's not the same as what you wrote down in the first post!

Can you give us a screenshot or photo of the original question?
10. (Original post by davros)
It's not the same as what you wrote down in the first post!

Can you give us a screenshot or photo of the original question?
I don't know sorry my friend just needed help on the question and that's all he sent me. Therefore, I just worked out what's in the bracket and then raised it to the power of -3/4 and it face me 16a^4.

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11. (Original post by Chittesh14)
I don't know sorry my friend just needed help on the question and that's all he sent me. Therefore, I just worked out what's in the bracket and then raised it to the power of -3/4 and it face me 16a^4.

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But it doesn't give you that

Even if you just consider the fraction (1/4)^-3/4 = 2root2 not 16
12. (Original post by TenOfThem)
But it doesn't give you that

Even if you just consider the fraction (1/4)^-3/4 = 2root2 not 16
Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.

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13. (Original post by Chittesh14)
Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.

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The negative power means reciprocal giving 4

The 1/4 power means fourth root giving root2

The 3 power means cube giving 2root2

No sign of 16
14. (Original post by Chittesh14)
Yeah, can u explain to me how you got there. I don't really know how to solve this question, my brother got something like that before and then he done it again to get 16a4.

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So u have 1/(1/4)^3/4 yes
Square root to give 1/(1/2)^3/2
Repeat again to give 1/(1/root2)^3

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15. (Original post by TenOfThem)
The negative power means reciprocal giving 4

The 1/4 power means fourth root giving root2

The 3 power means cube giving 2root2

No sign of 16
(Original post by physicsmaths)
So u have 1/(1/4)^3/4 yes
Square root to give 1/(1/2)^3/2
Repeat again to give 1/(1/root2)^3

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Oh right thanks guys, that's exactly what my brother done and got the answer 2 root 2. But, what happened to the a? Where does the letter a go.

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16. (Original post by Chittesh14)
Oh right thanks guys, that's exactly what my brother done and got the answer 2 root 2. But, what happened to the a? Where does the letter a go.

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Oh yh put that in there a^3/2

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17. (Original post by physicsmaths)
Oh yh put that in there a^3/2

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So, should the answer be 2 root 2, where is the a? lol.
It's like root 2 multiplied by a and then to the power of 3? is that what your saying.
18. (Original post by Chittesh14)
So, should the answer be 2 root 2, where is the a? lol.
It's like root 2 multiplied by a and then to the power of 3? is that what your saying.
Look we have done (1/4)^-3/4
No multiply it by (a^-2)^-3/4
If you use indices you should find that part extremely easy.

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19. (Original post by physicsmaths)
Look we have done (1/4)^-3/4
No multiply it by (a^-2)^-3/4
If you use indices you should find that part extremely easy.

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(a^-2)^-3/4 =
a^-2 = 1/a^2 then
(1/a^2)^-3/4 = 1 / (1/a^2)^3/4 =
(a^2)^3/4 = fourth root of a^2 = square root of a^2 = a, square root of a = root a.
cube root a = a root a?

So the answer should be 2 root 2 and a root a? im confused lol.
20. (Original post by Chittesh14)
(a^-2)^-3/4 =
a^-2 = 1/a^2 then
(1/a^2)^-3/4 = 1 / (1/a^2)^3/4 =
(a^2)^3/4 = fourth root of a^2 = square root of a^2 = a, square root of a = root a.
cube root a = a root a?

So the answer should be 2 root 2 and a root a? im confused lol.
Yes but u couldve just done -2x-3/4=3/2 so a^3/2 but yh thats aroota.

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